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A 50.0 g stone is attached to the bottom of a vertical spring and set vibrating. If the maximum and the period is \(0.500 \mathrm{~s}\), find the (a) spring constant of the spring, (b) amplitude of the motion, and (c) frequency of oscillation.

Short Answer

Expert verified
(a) Spring constant: 7.90 N/m, (b) Amplitude not specified, (c) Frequency: 2.00 Hz.

Step by step solution

01

Calculate the Spring Constant (a)

To find the spring constant, use the formula for the period of a mass-spring system: \[ T = 2\pi \sqrt{\frac{m}{k}} \] where: - \( T = 0.500 \) s (given),- \( m = 50.0 \text{ grams} = 0.0500 \text{ kg} \).Rearranging the formula to solve for \( k \), we have: \[ k = \frac{4\pi^2 m}{T^2} \]Plugging in the known values: \[ k = \frac{4\pi^2 \times 0.0500}{(0.500)^2} \approx 7.896 \text{ N/m} \] Thus, the spring constant is approximately 7.90 N/m.
02

Frequency of Oscillation (c)

To find the frequency, use the relationship between frequency \( f \) and period \( T \): \[ f = \frac{1}{T} \]Given \( T = 0.500 \text{ s} \): \[ f = \frac{1}{0.500} = 2.00 \text{ Hz} \]Thus, the frequency of oscillation is 2.00 Hz.
03

Amplitude of the Motion (b)

The amplitude is the maximum displacement from the equilibrium position, and it's usually given when referring to vibrating systems. Since the maximum displacement value isn't given explicitly, additional information or context is needed to calculate the amplitude. Typically, it would require specific data from the oscillatory motion such as energy or initial conditions that are not supplied here.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spring Constant
The spring constant, denoted as \( k \), is a measure of how stiff a spring is. The stiffer the spring, the larger the spring constant. In the context of simple harmonic motion, the spring constant influences how quickly the oscillating system returns to its equilibrium position.

In simple harmonic motion of a mass-spring system, the spring constant \( k \) can be determined from the period of oscillation \( T \) using the formula:
  • \[ T = 2\pi \sqrt{\frac{m}{k}} \]
This formula shows that the period \( T \) depends on both the mass \( m \) and the spring constant \( k \). By rearranging the formula, you can solve for \( k \):
  • \[ k = \frac{4\pi^2 m}{T^2} \]
In our exercise, with a mass \( m = 0.0500 \) kg and a period \( T = 0.500 \) s, we find the spring constant \( k \approx 7.90 \text{ N/m} \).This calculation shows that our spring is moderately stiff, allowing for a brisk return of the stone to equilibrium during vibration.
Frequency of Oscillation
The frequency of oscillation \( f \) refers to how often the oscillations occur within a given time frame, typically measured in hertz (Hz), which means oscillations per second. In a mass-spring system, the frequency provides insight into how many complete cycles of motion happen each second.

To find the frequency, use the relationship between period \( T \) and frequency \( f \):
  • \[ f = \frac{1}{T} \]
Given \( T = 0.500 \) s, the frequency is calculated to be \( 2.00 \text{ Hz} \).

This means the stone completes two full cycles of oscillation every second. The higher the frequency, the faster the oscillations occur, showing that this system has a fairly rapid oscillation, reinforcing the idea of the spring's moderate stiffness impacting the speed of vibrations.
Amplitude of Motion
The amplitude of motion in the context of oscillations refers to the maximum distance the oscillating object moves from its equilibrium position. It is a critical parameter as it represents the energy in the motion being directly related to how far the object is set into motion from rest.

In terms of simple harmonic motion, the lack of explicit initial conditions or external forces in the exercise typically means calculating the amplitude directly is not feasible without additional data like energy or force values at maximum displacement. This is often provided or measured in practical applications.

While this exercise doesn't provide specific data for amplitude calculation, it's essential to understand that amplitude is crucial in defining the extent of oscillation, dictating the maximum potential energy the system can possess based on how far the stone is stretched or compressed from the neutral position.

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Most popular questions from this chapter

Figure 15-34 shows block 1 of mass \(0.200 \mathrm{~kg}\) sliding to the right over a frictionless elevated surface at a speed of \(8.00 \mathrm{~m} / \mathrm{s}\). The block undergoes an elastic collision with stationary block 2 , which is attached to a spring of spring constant \(1208.5 \mathrm{~N} / \mathrm{m}\). (Assume that the spring does not affect the collision.) After the collision, block 2 oscillates in SHM with a period of \(0.140 \mathrm{~s}\), and block 1 slides off the opposite end of the elevated surface, landing a distance \(d\) from the base of that surface after falling height \(h=4.90 \mathrm{~m} .\) What is the value of \(d ?\)

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