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Gravitational force is a fundamental concept in physics that describes the attraction between two bodies with mass. It is the force that pulls objects toward the center of the Earth, which is why we experience weight. The formula to calculate gravitational force when near the Earth's surface is given by: \( F_g = mg \), where \( m \) represents the mass of the object, and \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \) on Earth).
For example, in our problem, a 5.00 kg object experiences a gravitational force of 49.05 N. This force acts downward, which aligns with our everyday experience of objects falling toward the Earth. Gravitational force is essential in computations involving objects in free fall or motion under gravity's influence.

Buoyant force is a concept that emerges when objects are submerged in a fluid. It is an upward force exerted by the fluid that opposes the weight of an object immersed in it. This force is why objects seem lighter when they are underwater.
To determine the buoyant force, we use the mass of the liquid displaced by the object: \( F_b = m_{\text{displaced}} g \).
In the provided exercise, the displaced liquid has a mass of 3.00 kg, yielding an upward buoyant force of 29.43 N. When solving problems involving buoyancy, recognizing this upward force is crucial as it affects the net force and thus the motion of the object.

Newton's Second Law of Motion is pivotal in understanding the relationship between force, mass, and acceleration. The law is succinctly described by the equation: \( F = ma \), where \( F \) is the net force applied to an object, \( m \) is its mass, and \( a \) is the resulting acceleration. This law states that the acceleration of an object depends directly on the net force acting upon it and inversely on its mass.
For the 5.00 kg object submerged in liquid, we calculated the net force to be 19.62 N downward. By substituting this value into Newton's second law formula, we determined the acceleration of the object to be 3.924 m/s². This calculation helps us predict how quickly and in what direction the object will move.

Kinematic equations deal with the motion of objects that are subject to constant acceleration. Out of the several kinematic equations, one very useful form, especially when computing displacement, is: \( s = ut + \frac{1}{2} at^2 \).
In this equation, \( s \) is the displacement, \( u \) is the initial velocity, \( a \) is acceleration, and \( t \) is the time elapsed.
For our object, we start with rest, so \( u = 0 \). By plugging in the acceleration \( a = 3.924 \, \text{m/s}^2 \) and the time \( t = 0.200 \, \text{s} \), we find the displacement to be 0.07848 m. The simplicity of this equation provides a clear method to determine how far an object moves when it starts from rest or with a known initial velocity under constant acceleration.