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A meter stick in frame \(S^{\prime}\) makes an angle of \(30^{\circ}\) with the \(x^ {\prime}\) axis. If that frame moves parallel to the \(x\) axis of frame \(S\) with speed \(0.90 \mathrm{c}\) relative to frame \(S\), what is the length of the stick as measured from \(S ?\)

Short Answer

Expert verified
The length of the stick as measured from frame \(S\) is approximately 0.626 meters.

Step by step solution

01

Identify the Known Variables

The angle of the meter stick with the \(x'\) axis is \(30^\circ\), and the speed \(v\) of the moving frame \(S'\) relative to the stationary frame \(S\) is \(0.90c\). The rest length of the stick is 1 meter, as implied by the term 'meter stick.'
02

Understand the Lorentz Contraction

Since the stick is moving parallel to its length with velocity \(0.90c\) relative to frame \(S\), the Lorentz contraction will affect its length. The contracted length \(L_x\) can be determined using the formula: \[ L_x = L_0 \sqrt{1 - \frac{v^2}{c^2}} \] where \(L_0\) is the proper length (1 meter).
03

Calculate the Contracted Length

Substitute the known values into the contraction formula: \[ L_x = 1 \times \sqrt{1 - (0.90)^2} = 1 \times \sqrt{1 - 0.81} = 1 \times \sqrt{0.19} \approx 0.436 \text{ meters} \]
04

Consider Stick Orientation and Effective Length

Due to the angle of the meter stick in its rest frame, the actual observed length in \(S\) needs to be resolved into components. The contracted length parallel to the \(x'\) axis is shortened by the factor calculated while the perpendicular component remains unchanged.
05

Resolve Angled Stick into Components

Find the components along \(x'\) and \(y'\) axes. The length along the \(x'\) axis is \( L_{x', ||} = L_0 \cos(30^\circ) \) and the \(y'\) component is \( L_{x', \perp} = L_0 \sin(30^\circ) \). The effective length in \(S\) is given by: \[ L = \sqrt{(L_{x', ||} \cdot \sqrt{1 - \frac{v^2}{c^2}})^2 + L_{x', \perp}^2} \] Substituting the known values gives: \[ L_{x', ||} = 1 \times \cos(30^\circ) = \frac{\sqrt{3}}{2} \] \[ L_{x', \perp} = 1 \times \sin(30^\circ) = 0.5 \]
06

Calculate the Effective Length in Frame S

Use the derived formulas: \[ L = \sqrt{\left(\frac{\sqrt{3}}{2} \times 0.436\right)^2 + 0.5^2} \]\[ L \approx \sqrt{(0.377)^2 + 0.25} \]\[ L \approx \sqrt{0.142 + 0.25} \]\[ L \approx \sqrt{0.392} \approx 0.626 \text{ meters} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relativistic Effects
Relativistic effects play a crucial role when evaluating objects moving at significant fractions of the speed of light. As things speed up to velocities close to that of light (denoted as 'c'), several effects appear that are not observable at lower speeds. One key relativistic effect is time dilation, where time seems to pass differently depending on your speed. Another critical effect is Lorentz contraction, which specifically involves the contraction of length of objects that are moving at high speeds.
Understanding these effects is fundamental to grasping modern physics principles, particularly those that are part of Einstein's theory of relativity. As objects travel at speeds close to c, traditional Newtonian physics no longer applies and relativistic physics takes over. This is why we see phenomena like length contraction and time dilation, which have been verified through numerous experiments.
  • Time dilation: As velocity increases, time "slows down."
  • Length contraction: Objects appear shorter in the direction of motion.
  • Mass increase: Objects appear to gain mass as they approach the speed of light.
These effects are demonstrated in various physics problems, such as calculating the length of objects like sticks or meter sticks when they are angled and moving at a significant fraction of light speed.
Length Contraction
Length contraction is a fascinating aspect of Einstein's theory of relativity. When an object moves relative to an observer at speeds approaching the speed of light, its length appears shorter along the direction of motion. This is known as Lorentz contraction.
Consider a meter stick moving at 0.90c along an observer's frame of reference. If stationary, the stick would be a full meter long. As it speeds up, however, the stick contracts. The degree of contraction can be calculated using the Lorentz contraction formula:

\[ L = L_0 \sqrt{1 - \frac{v^2}{c^2}} \]

where \( L_0 \) is the proper or rest length of the object (1 meter in the case of the meter stick), \( v \) is the velocity of the object relative to the observer, and \( c \) is the speed of light. This formula shows how the object's length decreases as its speed approaches the speed of light.
In our specific example, the meter stick is also positioned at a 30-degree angle to its direction of motion in its own rest frame. This adds a layer of complexity because while its length in the direction of motion is contracted, the perpendicular component of the stick—the part sticking out at an angle—remains unchanged.
This results in the need to resolve the stick into components, calculate the contraction for the parallel part, and then combine them to determine the effective length as seen from a stationary observer.
Frame of Reference
A frame of reference is crucial for understanding motion and the different effects that come with it, like length contraction. Imagine two systems, usually denoted as \(S\) and \(S'\). Each frame is a way to measure and observe physical phenomena like position, velocity, and time. A moving frame (\(S'\)), might see things quite differently from a stationary one (\(S\)).
In our example, we consider a stick moving with speed 0.90c relative to frame \(S\). From its rest frame \(S'\) perspective, the stick retains its full length, since it's not moving relative to itself. However, if you observe the stick from \(S\), which sees \(S'\) speeding past at a significant fraction of the speed of light, then relativistic effects kick in.
The concept of relative motion changes how measurements like length and time appear. For the stationary observer in \(S\), measurements need adjustments for relativity. This entails:
  • Recognizing that each observer measures their own version of reality.
  • Appreciating the role of relative velocity when considering the effects on length and time.
  • Remembering that the laws of physics remain consistent across all inertial frames.
Understanding frames of reference helps make sense of why objects appear to contract in length or experience time differently. Without considering the frame of reference, calculations and observations in relativistic physics would be complex and misleading.

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Most popular questions from this chapter

An iron anchor of density \(7870 \mathrm{~kg} / \mathrm{m}^{3}\) appears \(200 \mathrm{~N}\) lighter in water than in air. (a) What is the volume of the anchor? (b) How much does it weigh in air?

The length of a spaceship is measured to be exactly half its rest length. (a) To three significant figures, what is the speed parameter \(\beta\) of the spaceship relative to the observer's frame? (b) By what factor do the spaceship's clocks run slow relative to clocks in the observer's frame?

The car-in-the-garage problem. Carman has just purchased the world's longest stretch limo, which has a proper length of \(L_{c}=30.5 \mathrm{~m} .\) In Fig. \(37-32 a,\) it is shown parked in front of a garage with a proper length of \(L_{g}=6.00 \mathrm{~m}\). The garage has a front door (shown open) and a back door (shown closed). The limo is obviously longer than the garage. Still, Garageman, who owns the garage and knows something about relativistic length contraction, makes a bet with Carman that the limo can fit in the garage with both doors closed. Carman, who dropped his physics course before reaching special relativity, says such a thing, even in principle, is impossible. To analyze Garageman's scheme, an \(x_{c}\) axis is attached to the limo, with \(x_{c}=0\) at the rear bumper, and an \(x_{k}\) axis is attached to the garage, with \(x_{g}=0\) at the (now open) front door. Then Carman is to drive the limo directly toward the front door at a velocity of \(0.9980 c\) (which is, of course, both technically and financially impossible). Carman is stationary in the \(x_{c}\) reference frame; Garageman is stationary in the \(x_{z}\) reference frame. There are two events to consider. Event 1 : When the rear bumper clears the front door, the front door is closed. Let the time of this event be zero to both Carman and Garageman: \(t_{\mathrm{s} 1}=t_{c 1}=0\). The event occurs at \(x_{c}=x_{g}=0 .\) Figure \(37-32 b\) shows event 1 according to the \(x_{g}\) reference frame. Event 2 : When the front bumper reaches the back door, that door opens. Figure \(37-32 c\) shows event 2 according to the \(x_{g}\) reference frame. According to Garageman, (a) what is the length of the limo, and what are the spacetime coordinates (b) \(x_{R 2}\) and (c) \(t_{g 2}\) of event \(2 ?\) (d) For how long is the limo temporarily "trapped" inside the garage with both doors shut? Now consider the situation from the \(x_{c}\) reference frame, in which the garage comes racing past the limo at a velocity of \(-0.9980 \mathrm{c}\). According to Carman, (e) what is the length of the passing garage, what are the spacetime coordinates (f) \(x_{c 2}\) and \((g) t_{c 2}\) of event \(2,(h)\) is the limo ever in the garage with both doors shut, and (i) which event occurs first? (j) Sketch events 1 and 2 as seen by Carman. (k) Are the events causally related; that is, does one of them cause the other? (I) Finally, who wins the bet?

An airplane has rest length \(40.0 \mathrm{~m}\) and speed \(630 \mathrm{~m} / \mathrm{s} .\) To a ground observer, (a) by what fraction is its length contracted and (b) how long is needed for its clocks to be \(1.00 \mu \mathrm{s}\) slow?

(a) If \(m\) is a particle's mass, \(p\) is its momentum magnitude, and \(K\) is its kinctic energy, show that $$ m=\frac{(p c)^{2}-K^{2}}{2 K c^{2}} $$ (b) For low particle speeds, show that the right side of the equation reduces to \(m\). (c) If a particle has \(K=55.0 \mathrm{MeV}\) when \(p=\) \(121 \mathrm{MeV} i c,\) what is the ratio \(\mathrm{m} / \mathrm{m}_{e}\) of its mass to the clectron mass?

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