/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 52 The Sun's center is at one focus... [FREE SOLUTION] | 91Ó°ÊÓ

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The Sun's center is at one focus of Earth's orbit. How far from this focus is the other focus, (a) in meters and (b) in terms of the solar radius, \(6.96 \times 10^{8} \mathrm{~m}\) ? The eccentricity is 0.0167 , and the semimajor axis is \(1.50 \times 10^{11} \mathrm{~m} .\)

Short Answer

Expert verified
The other focus is \(5.01 \times 10^{9} \text{ m}\) or \(\approx 7.20\) solar radii away.

Step by step solution

01

Understanding the Problem

We are asked to find the distance between the two foci of Earth's elliptical orbit around the Sun. This involves understanding the geometry of an ellipse. Given the distance of 1 focus (Sun's center) and the eccentricity, we need to find the distance to the other focus.
02

Ellipse Geometry

The formula to find the distance "c" between the center and a focus of an ellipse is given by:\[ c = a \times e \]where \(a\) is the semimajor axis and \(e\) is the eccentricity.
03

Calculating "c"

We are given \(a = 1.50 \times 10^{11} \text{ m}\) and \(e = 0.0167\). Substituting these values into the formula:\[ c = 1.50 \times 10^{11} \times 0.0167 = 2.505 \times 10^{9} \text{ m}\]
04

Distance Between Foci

In an ellipse, the two foci are 2c apart. So the distance between the foci is:\[ 2c = 2 \times 2.505 \times 10^{9} = 5.01 \times 10^{9} \text{ m}\]
05

Converting Distance to Solar Radii

To convert the distance from meters to solar radii (where the solar radius is \(6.96 \times 10^{8} \text{ m}\)), divide the distance by the solar radius:\[ \frac{5.01 \times 10^{9}}{6.96 \times 10^{8}} \approx 7.20 \text{ solar radii}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Eccentricity
Eccentricity is a key parameter when discussing elliptical orbits, such as Earth's path around the Sun. It measures how much an orbit deviates from being a perfect circle. Eccentricity is represented by the letter "e" and ranges from 0 to 1. A value of 0 is a perfect circle, while values close to 1 indicate more elongated orbits.
In the context of Earth's orbit, the eccentricity is relatively low, at 0.0167, which means the orbit is nearly circular. This low eccentricity ensures that the distance between Earth and Sun does not vary drastically throughout the year. This helps maintain Earth’s relatively stable climate.
To determine how eccentricity affects the orbit, we use the formula \( c = a \times e \), where \( c \) is the distance from the center of an ellipse to a focus, \( a \) is the semimajor axis, and \( e \) is the eccentricity. This demonstrates how eccentricity directly impacts the separation of the foci in Earth’s seemingly circular but actually elliptical orbit.
Semimajor Axis
The semimajor axis is a fundamental component in understanding elliptical orbits. It is the longest radius of an ellipse, extending from the center to the furthest edge. In astronomical terms, it represents the average distance from a planet to the Sun over the course of a year.
In our exercise, the semimajor axis of Earth's orbit is given as \( 1.50 \times 10^{11} \text{ m} \) (or 150 million kilometers). This is significant because it helps us understand the scale of Earth's orbit and use it in various calculations, such as determining orbital periods or applying Kepler's laws.
By knowing the semimajor axis, along with the eccentricity, we can calculate specific characteristics of the orbit, like the distance between the foci. This is performed mathematically by the equation \( c = a \times e \), showcasing the portrait of Earth's orbit.
Solar Radius
The solar radius is an astronomical unit used to express distances in terms of the Sun’s radius. This provides a convenient way to compare distances in the solar system to the size of the Sun.
The solar radius is approximately \( 6.96 \times 10^{8} \text{ m} \) (or 696,000 kilometers). In astronomical studies, many distances are converted into solar radii to simplify their representation. For example, the distance between the two foci of Earth's orbit, calculated as \( 5.01 \times 10^{9} \text{ meters} \), converts to about 7.20 solar radii.
This conversion is accomplished by dividing the distance by the solar radius, offering a more intuitive sense of these enormous distances. Using solar radii helps students and astronomers alike to relate and comprehend astronomical scales by rooting them in a familiar unit based on the Sun itself.

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Most popular questions from this chapter

Observations of the light from a certain star indicate that it is part of a binary (two-star) system. This visible star has orbital speed \(v=270 \mathrm{~km} / \mathrm{s}\) orbital period \(T=1.70\) days, and approximate mass \(m_{1}=6 M_{s},\) where \(M_{s}\) is the Sun's mass, \(1.99 \times 10^{30} \mathrm{~kg}\). Assume that the visible star and its companion star, which is dark and unseen, are both in circular orbits (Fig. \(13-47\) ). What integer multiple of \(M_{s}\) gives the approximate \(\operatorname{mass} m_{2}\) of the dark star?

Zero, a hypothetical planet, has a mass of \(5.0 \times 10^{23} \mathrm{~kg},\) a radius of \(3.0 \times 10^{6} \mathrm{~m}\) and no atmosphere. A \(10 \mathrm{~kg}\) space probe is to be launched vertically from its surface. (a) If the probe is launched with an initial energy of \(5.0 \times 10^{7} \mathrm{~J},\) what will be its kinetic energy when it is \(4.0 \times 10^{6} \mathrm{~m}\) from the center of Zero? (b) If the probe is to achieve a maximum distance of \(8.0 \times 10^{6} \mathrm{~m}\) from the center of Zero, with what initial kinetic energy must it be launched from the surface of Zero?

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A satellite is in a circular Earth orbit of radius \(r .\) The area \(A\) enclosed by the orbit depends on \(r^{2}\) because \(A=\pi r^{2} .\) Determine how the following properties of the satellite depend on \(r\) : (a) period, (b) kinetic energy, (c) angular momentum, and (d) speed.

A satellite is put in a circular orbit about Earth with a radius equal to one- half the radius of the Moon's orbit. What is its period of revolution in lunar months? (A lunar month is the period of revolution of the Moon.)

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