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Two spheres of mass \(m\) and a third sphere of mass \(M\) form an equilateral triangle, and a fourth sphere of mass \(m_{4}\) is at the center of the triangle. The net gravitational force on that central sphere from the three other spheres is zero. (a) What is \(M\) in terms of \(m ?\) (b) If we double the value of \(m_{4},\) what then is the magnitude of the net gravitational force on the central sphere?

Short Answer

Expert verified
(a) \( M = m \); (b) Force remains zero.

Step by step solution

01

Understanding the Setup

Consider an equilateral triangle formed by spheres of mass \( m, m, \) and \( M \). A fourth sphere of mass \( m_4 \) is placed at the center of this triangle, equidistant from all three spheres.
02

Forces on the Central Sphere

Each sphere exerts a gravitational force on \( m_4 \). Since the system is symmetrical, the forces exerted by the two spheres of mass \( m \) will have components in opposite directions that cancel out. The force from the sphere with mass \( M \) will also have components, with a portion directed towards the center of the triangle.
03

Net Force is Zero

For the net force on the central sphere \( m_4 \) to be zero, the vector sum of all forces from the three spheres must cancel. Mathematically, this requires that the forces from the three spheres add up to zero.
04

Calculating the Required Mass M

Using symmetry, equate the net force of the two spheres of mass \( m \) to the force exerted by sphere \( M \). For the forces to cancel out exactly, \( M = m \). The symmetry and balance of forces in the equilateral triangle ensure this equality.
05

Effect of Doubling the Central Mass

If \( m_4 \) is doubled, the gravitational forces on it from each sphere are subsequently doubled. However, the configuration and alignment of forces remain the same – symmetrically balanced. Thus, the magnitude of the net force remains zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass and Weight
Mass and weight are fundamental concepts in physics that often get confused. **Mass** is a measure of the amount of matter in an object, and it is measured in kilograms. Mass does not change, regardless of location or gravitational forces.

**Weight**, on the other hand, is the force exerted by gravity on an object. It is calculated as the product of mass and the gravitational acceleration of the environment, given by the formula: \[ W = m imes g \]where \( W \) is weight, \( m \) is mass, and \( g \) is the acceleration due to gravity (approximately 9.81 m/s² on Earth).

In our exercise, we are dealing with different masses which exert gravitational forces. The weight of the spheres is not a direct concern here, because gravitational calculations focus on the interaction between masses rather than their weight.
Equilateral Triangle
An equilateral triangle is a triangle where all three sides are of equal length. Additionally, all of its internal angles are equal, each measuring 60 degrees. This creates a highly symmetrical shape, which significantly simplifies many physical and mathematical problems.

In the context of gravitational forces, placing masses at the vertices of an equilateral triangle provides a situation where symmetry plays a key role in balancing forces. In our exercise, the central mass is influenced evenly from all three sides because of this symmetry. This helps in determining that the net force is zero due to equal magnitude of forces in opposite directions, perfectly canceling each other out.

The concept of symmetry is crucial here, as it underpins our understanding that the net gravitational force on the central sphere is zero, which allows us to determine the required masses' relationships.
Symmetry in Physics
Symmetry is an important principle in physics as it can drastically simplify the analysis of complex systems. Symmetrical arrangements often lead to interesting invariants and conserved quantities.

For instance, in a system where forces are symmetrically distributed, like our equilateral triangle, we can often predict certain outcomes without making complex calculations. In our problem, symmetry assures us that the gravitational forces from the masses on the vertices of the equilateral triangle cancel each other out at the center.

By making use of symmetry, we understand that the sum of the forces acting on the center sphere must be zero, effectively allowing us to conclude that two masses \( m \) and mass \( M \) must be equal. Symmetry ensures that the direction and magnitude balance precisely despite doubling the central sphere's mass; the symmetry of the forces remains unchanged, leaving the net force unaffected.

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Most popular questions from this chapter

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