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Starting from rest at \(t=0,\) a wheel undergoes a constant angular acceleration. When \(t=2.0 \mathrm{~s},\) the angular velocity of the wheel is \(5.0 \mathrm{rad} / \mathrm{s} .\) The acceleration continues until \(t=20 \mathrm{~s},\) when it abruptly ceases. Through what angle does the wheel rotate in the interval \(t=0\) to \(t=40 \mathrm{~s} ?\)

Short Answer

Expert verified
The wheel rotates through 1500 radians.

Step by step solution

01

Determine Angular Acceleration

To find the angular acceleration, use the formula \( \omega = \alpha t \) for constant acceleration, where \( \omega \) is the angular velocity, and \( \alpha \) is the angular acceleration.At \( t = 2 \, \text{s} \), \( \omega = 5 \, \text{rad/s} \).Thus, we have \[ 5 = \alpha \cdot 2 \].Solve for \( \alpha \):\[ \alpha = \frac{5}{2} = 2.5 \, \text{rad/s}^2 \].
02

Calculate Angle from 0 to 20 seconds

During the interval from 0 to 20 seconds, the wheel has a constant angular acceleration.Use the formula \[ \theta = \omega_0 t + \frac{1}{2} \alpha t^2 \] to find the angle, where \( \theta \) is the angular displacement and \( \omega_0 = 0 \) since it starts from rest.Substitute the values \( \alpha = 2.5 \, \text{rad/s}^2 \) and \( t = 20 \, \text{s} \):\[ \theta = 0 + \frac{1}{2} \times 2.5 \times (20)^2 \]\[ \theta = 0.5 \times 2.5 \times 400 \]\[ \theta = 500 \, \text{rad} \].
03

Calculate Angular Velocity at 20 seconds

Before calculating the angle from 20 to 40 seconds, identify the angular velocity at \( t = 20 \, \text{s} \) using \( \omega = \omega_0 + \alpha t \).Substitute the known values:\[ \omega = 0 + 2.5 \times 20 \]\[ \omega = 50 \, \text{rad/s} \].
04

Calculate Angle from 20 to 40 seconds

From 20 to 40 seconds, the wheel rotates at a constant angular velocity found in Step 3.Use the formula \( \theta = \omega t \) for constant rotation, where \( t = 20 \, \text{s} \) (from 20 to 40 seconds).Substitute \( \omega = 50 \, \text{rad/s} \):\[ \theta = 50 \times 20 \]\[ \theta = 1000 \, \text{rad} \].
05

Total Angular Displacement

Add the angular displacements from 0 to 20 seconds and from 20 to 40 seconds to find the total rotation:\[ \theta_{\text{total}} = 500 + 1000 \]\[ \theta_{\text{total}} = 1500 \, \text{rad} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Acceleration
Angular acceleration is a measure of how quickly an object's angular velocity changes with respect to time. It is denoted by the symbol \( \alpha \). In physics, when we talk about angular motion, angular acceleration plays a key role. If a wheel starts from rest and begins to spin, angular acceleration tells us how fast it is speeding up.

To find angular acceleration when starting from rest, you can use the formula:
  • \( \omega = \alpha t \)
rwhere \( \omega \) is angular velocity and \( t \) is time. If the wheel’s angular velocity is known at a certain time, angular acceleration can be determined by rearranging the formula:
  • \( \alpha = \frac{\omega}{t} \)
For example, if a wheel reaches an angular velocity of \( 5 \, \text{rad/s} \) after \( 2 \, \text{s} \), the angular acceleration \( \alpha \) is \( 2.5 \, \text{rad/s}^2 \). This concept helps to understand how quickly the wheel speeds up over time.
Angular Displacement
Angular displacement refers to the angle through which an object rotates, measured in radians. It represents how far the object has turned or rotated. During motion, understanding angular displacement helps visualize the extent of rotation from the start.

For an object starting from rest and undergoing constant angular acceleration, the angle can be calculated using the formula:
  • \( \theta = \omega_0 t + \frac{1}{2} \alpha t^2 \)
Here, \( \omega_0 \) is the initial angular velocity, \( \alpha \) the angular acceleration, and \( t \) the time. If the object starts from rest, \( \omega_0 = 0 \). For the example where \( \alpha = 2.5 \, \text{rad/s}^2 \) and \( t = 20 \, \text{s} \), the angular displacement is \( 500 \, \text{rad} \).

This equation shows how the angle is not just depending upon angular acceleration, but also on the square of time. It's crucial when determining total rotational progress, like how far a wheel has turned.
Angular Velocity
Angular velocity indicates how quickly an object rotates or spins. It is symbolized by \( \omega \) and typically measured in radians per second. In simple terms, it tells us how fast the angle is changing as the object rotates.

When an object experiences constant angular acceleration, the angular velocity at any time \( t \) can be found using:
  • \( \omega = \omega_0 + \alpha t \)
If the object starts from rest, \( \omega_0 = 0 \). For instance, with \( \alpha = 2.5 \, \text{rad/s}^2 \) and \( t = 20 \, \text{s} \), the angular velocity becomes \( 50 \, \text{rad/s} \).

Understanding angular velocity is critical in scenarios where rotation continues at a steady rate. Such as between \( t = 20 \) and \( t = 40 \, \text{s} \) in our wheel example, where the velocity remains constant, exhibiting how persistent rotation translates to greater displacement.

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