91Ó°ÊÓ

Length of the wire, L=1.50 m

Mass of the wire, m=8.70 g or 0.00870 kg

Tension in the wire, T=120 N

Use the formula for speed in terms of tension and mass per unit length. To find the wavelength, we use the length of the wire. To find the frequency, use velocity from part (a) and wavelength from part (b) and (c).

Formula:

The speed of a string,$v=\sqrt{\frac{T}{\mathrm{μ}}}..........\left(1\right)$

The speed of a wave,$v=f×\mathrm{λ}........\left(2\right)$

The linear density of a string,$\mathrm{μ}=\frac{m}{L}...........\left(3\right)$

Using equation (3), we get the linear density as follows:

$\begin{array}{l}\mathrm{μ}=\frac{0.0087}{1.5}\\ =5.8×{10}^{-3}kg/\mathrm{m}\end{array}$

Now, using the given values in equation (1), we get the speed of the wave as:

$$\begin{gathered} v=\sqrt{\frac{120}{5.8×{10}^{-3}}} \\ =143.83\frac{m}{s} \\ ≈144m/s \end{gathered}$$

Hence, the value of the speed is 144 m/s

Now the wavelength for one loop standing wave is given as:

$\begin{array}{l}{\mathrm{λ}}_1=L×2\\ =1.5×2\\ =3.00m\end{array}$

Hence, the value of wavelength for one-loop wave is 3.00 m

Now for two loop standing wave

$$\begin{gathered} {\mathrm{λ}}_2=L \\ =1.5m \end{gathered}$$

Hence, the value of wavelength for two loops is 1.5 m

Now, using equation (2) and given values, we get the frequency of one loop as:

$\begin{array}{l}144={\mathrm{f}}_1×3\\ {\mathrm{f}}_1=48.0\mathrm{Hz}\end{array}$

Hence, the value of frequency for one loop is 48.0 Hz

Now, frequency of two loop using equation (2) and the given values is given as:

$\begin{array}{l}144=f_2×1.5\\ f_2=96\mathrm{Hz}\end{array}$

Hence, the value of frequency of two-loop wave is 96 Hz