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If d鈬赌1=3i^-2j^+4k^and d鈬赌2=-5i^+2j^-k^then what is (d鈬赌1+d鈬赌2).(d鈬赌14d鈬赌2)?

Short Answer

Expert verified

The product,(d鈬赌1+d鈬赌2).(d鈬赌14d鈬赌2)is equal to 0.

Step by step solution

01

Vector operations

The dot product of perpendicular vectors is equal to zero. The cross-product of two vectors results in a vector that is perpendicular to both vectors.

Find the value for d鈬赌1+d鈬赌2and d鈬赌14d鈬赌2separately and then take the dot product of them to find the required answer.

The given vectors are,

d1鈬赌=3i^-2j^+4k^d鈬赌2=-5j^+2j^-k^

02

Calculating the cross and dot product

d鈬赌1+d鈬赌2will lie in the same plane i.e., in the plane of d鈬赌1andd鈬赌2.

d鈬赌14d鈬赌2 will lie in the plane which is perpendicular to the plane of d鈬赌1andd鈬赌2.

As they are perpendicular to each other the dot product of d鈬赌1+d鈬赌2andd鈬赌14d鈬赌2will be zero.

role="math" localid="1656309525133" d鈬赌1+d鈬赌2.d鈬赌14d鈬赌2=0

Thus, the dot product of d鈬赌1+d鈬赌2and d鈬赌14d鈬赌2is equal to 0.

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