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A horizontal platform in the shape of a circular disk rotates on a frictionless bearing about a vertical axle through the centre of the disk. The platform has a mass of 150kg, a radius of2.0m, and a rotational inertia of300kg.m2about the axis of rotation. A60kgstudent walks slowly from the rim of the platform toward the centre. If the angular speed of the system is1.5rad/swhen the student starts at the rim, what is the angular speed when she is0.50mfrom the centre?

Short Answer

Expert verified

Angular speed of student when she is at 0.5mfrom the center of a circular disk isÓ¬f=2.6rads2.

Step by step solution

01

Step 1: Given

  1. Mass of the platform,m=150kg
  2. Radius of platform,r=2.0m
  3. Initial angular speed of the systemÓ¬i=1.5rad/s
  4. Distance of the student from the center,R=0.5m
  5. Idisk=300kg.m2
02

Determining the concept

Calculate initial and final rotational inertias. Then, apply law of conservation of angular momentum to find final angular speed. According tothe conservation of momentum, momentum of a system is constant if no external forces are acting on the system.

Formula are as follow:

Istudent=Mstudent×R2

Initialangularmomentum=Finalangularmomentum

Where,Istudent is moment of inertia of student, Mstudentis mass of student and R is radius.

03

Determining the angular speed of student when she is at 0.5 m from the center of a circular disk 

The initial rotational inertia of the system,

I=Idisk+Istudent

I=300+60×22=540kg.m2

The final rotational inertia when she reaches0.5mfrom the center,

If=Idisk+IstudentIf=300+60×0.52=315kg.m2

According to law of conservation of angular momentum:

Li=LfIiӬi=IfӬf540×1.5=315×Ӭf

Hence,

Ó¬f=2.6rads2

Hence,angular speed of student when she is at0.5mfrom the center of a circular disk isÓ¬f=2.6rads2.

Therefore, using law of conservation of angular momentum, the final angular velocity of the student at the given distance can be found.

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