/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q96P Question:聽A 2.50 MeV electron m... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 37: Q96P (page 1152)

Question:A 2.50 MeV electron moves perpendicularly to a magnetic field in a path with a 3.0 cm radius of curvature. What is the magnetic field B? (See Problem 53)

Short Answer

Expert verified

The magnetic field for the electron is 0.178T.

Step by step solution

01

Identification of given data

The energy of electron is E=2.50MeV

The radius of curvature is r=3cm

The magnetic field for the electron is found by equating the necessary centripetal force by magnetic force on the electron.

02

Determination of magnetic field for electron

The magnetic field for electron is given as:

B=2mEqr

Here, q is the charge of electron and its value is 1.6脳10-19C , m is the mass of electron and its value is 9.1脳10-31kg

Substitute all the values in the above equation.

B=29.1脳10-31kg2.50MeV1.6脳10-13J1MeV1.6脳10-19C3cm10-2m1cmB=0.178t

Therefore, the magnetic field for the electron is 0.178T.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The mean lifetime of stationary muons is measured to be 2.2000渭s. The mean lifetime of high-speed muons in a burst of cosmic rays observed from Earth is measured to be 16.000渭s. To five significant figures, what is the speed parameter 尾of these cosmic-ray muons relative to Earth?

To circle Earth in low orbit, a satellite must have a speed of about 2.7 x 104 km/h. Suppose that two such satellites orbit Earth in opposite directions. (a) What is their relative speed as they pass, according to the classical Galilean velocity transformation equation? (b) What fractional error do you make in (a) by not using the (correct) relativistic transformation equation?

Question: What is尾 for a particle with (a) K=2.00Eoand (b)E=2.00Eo ?

Question:(a) If m is a particle鈥檚 mass, p is its momentum magnitude, and K is its kinetic energy, show that

m=pc2-K22Kc2

(b) For low particle speeds, show that the right side of the equation reduces to m. (c) If a particle has K = 55.0 MeV when p=121 MeV/c, what is the ratio m/me of its mass to the electron mass?

Figure 37-20 shows the triangle of Fig 37-14 for six particles; the slanted lines 2 and 4 have the same length. Rank the particles according to (a) mass, (b) momentum magnitude, and (c) Lorentz factor, greatest first. (d) Identify which two particles have the same total energy. (e) Rank the three lowest-mass particles according to kinetic energy, greatest first.
See all solutions

Recommended explanations on Physics Textbooks

Electricity and Magnetism

Read Explanation

Rotational Dynamics

Read Explanation

Thermodynamics

Read Explanation

Electromagnetism

Read Explanation

Torque and Rotational Motion

Read Explanation

Dynamics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.