91Ó°ÊÓ

The average of the automobile is $x=12.75\text{km}/\text{L}$

The heat of combustion of gasoline is $H=3.65×{10}^7\text{J}/\text{L}$

The mass of the aspirin tablet is $m=320\text{mg}$

The volume of the gasoline is found by dividing the rest energy of one tablet by heat of combustion then multiply this volume with average of the automobile to find the distance travelled by automobile.

The rest energy of aspirin tablet is given as:

$E_0=m{c}^2$

Substitute all the values in equation.

$$\begin{gathered} E_0=\left(320\text{mg}\right)\left(\frac{1\text{kg}}{{10}^6\text{mg}}\right){\left(3×{10}^8\text{m}/\text{s}\right)}^2 \\ {E}_0=2.88×{10}^{13}\text{J} \end{gathered}$$

The volume of the gasoline is given as:

$V=\frac{E_0}{H}$

Substitute all the values in equation.

$$\begin{gathered} V=\frac{2.88×{10}^{13}\text{J}}{3.65×{10}^7\text{J}/\text{L}} \\ V=7.89×{10}^5\text{L} \end{gathered}$$

The distance for the energy equivalent is given as:

$d=x·V$

Substitute all values in above equation.

$$\begin{gathered} d=\left(12.75\text{km}/\text{L}\right)\left(7.89×{10}^5\text{L}\right) \\ d=1.01×{10}^7\text{km} \end{gathered}$$

Therefore, the distance for energy equivalent of the aspirin tablet is $1.01×{10}^7\text{km}$.