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${}^3\text{He}$and ${}^4\text{He}$are two isotopes of helium.

Fermion

Any particle with an odd half-integer spin, such as 1/2 , 3/2 and so on, is referred to as a fermion.

Bosons

Bosons are particles with integer spins 0,1,2.

Fermions have a half-integer spin and bosons have an integer spin.

In localid="1663128163011" ${}^4\text{He}$ total spin is zero since its neutron and proton spins are positioned in opposition to one another Therefore it is a boson.

${}^3\text{He}$has two protons and one neutron The proton spins in ${}^3\text{He}$are oppositely aligned so they have total spin 0, whereas the last neutron has spin 1/2. ${}^3\text{He}$has a 1/2 spin as a result it is a fermion.

Since both are not fermions therefore this statement is not true.

Fermions have a half-integer spin, whereas bosons have an integer spin.

${}^4\text{He}$has two protons and two neutrons.

${}^4\text{He}$has total spin is zero since its neutron and proton spins are positioned in opposition to one another. Therefore it is a boson.

${}^3\text{He}$has two protons and one neutron The proton spins in ${}^3\text{He}$are oppositely aligned (total spin 0 ), whereas the last neutron has spin 1/2 . ${}^3\text{He}$has a spin 1/2 as a result it is a fermion.

Since both are not boson therefore this statement is not true.

Fermions have a half-integer spin and bosons have an integer spin.

${}^4\text{He}$has two protons and two neutrons.

${}^4\text{He}$has total spin zero since its neutron and proton spins are positioned in opposition to one another Therefore it is a boson.

${}^3\text{He}$has two protons and one neutron The proton spins in ${}^3\text{He}$are oppositely aligned (total spin 0), whereas the last neutron has spin 1/2 . ${}^3\text{He}$has a 1/2 spin as a result it is a fermion.

Since ${}^3\text{He}$not is a boson and ${}^4\text{He}$is not a fermion therefore this statement is not true.

Fermions have a half-integer spin and bosons have an integer spin.

${}^4\text{He}$has two protons and two neutrons.

${}^4\text{He}$has total spin zero since its neutron and proton spins are positioned in opposition to one another Therefore it is a boson.

${}^3\text{He}$has two protons and one neutron The proton spins in ${}^3\text{He}$are oppositely aligned (total spin 0 ), whereas the last neutron has spin 1/2 . ${}^3\text{He}$has a 1/2 spin as a result it is a fermion.

Since is a fermion and ${}^4\text{He}$is a boson therefore this statement is true