/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q53P In Fig.8.52, a 3.5 kg block is a... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Fig.8.52, a 3.5 kg block is accelerated from rest by a compressed spring of spring constant 640 N/m. The block leaves the spring at the spring’s relaxed length and then travels over a horizontal floor with a coefficient of kinetic friction μk=0.25.The frictional force stops the block in distance D = 7.8 m. What are (a) the increase in the thermal energy of the block–floor system (b) the maximum kinetic energy of the block, and (c) the original compression distance of the spring?


Short Answer

Expert verified

a) The increase in thermal energy of block-floor system 67 J

b) The maximum kinetic energy of the block-floor system 67 J

c) The original compression distance of the spring46 cm

Step by step solution

01

Listing the given quantities

The mass of the block,m=3.5kg

The spring constant of the spring,k=640N/m

The coefficient of friction,μk=0.25

The distance at which the blocks comes to rest,D=7.8m

02

Understanding the concept of conservation of energy

The total energy of the block-floor system is conserved during motion. The spring is initially compressed. When the block leaves the spring at its relaxed position, the potential energy is converted to kinetic energy of the block. As the block continues its motion, it loses its energy to the frictional force of the floor as it finally comes to rest.

Formula:

K.E=12mv2P.Espring=12kx2Eth=Ffx

03

Step 3(a): Calculation of increase in thermal energy of the block- floor system

The increase in thermal energy of the block-floor system occurs because of the friction between the block and the floor. Hence

Eth=FfxEth=μkmgD=0.25×3.5kg×9.8m/s2×7.8m=66.9J~67J

Hence, the increase in thermal energy of block-floor system = 67 J

04

Step 4(b): Calculation of maximum kinetic energy of block floor system

The block comes to rest after travelling distance D. Hence, the kinetic energy of the block at the start of this motion is completely converted to the thermal energy. So that we write

Eth=KE

Hence, the maximum kinetic energy of the block = 67 J

05

Step 5(c): Calculation of original compression of the spring

When the block leaves the spring, it is the relaxed position of the spring. So the kinetic energy of the block at this moment is potential energy of the compressed spring.

So we write,

K.Eblock=P.Espring12kx2=67J12×640N/m×x2=67Jx2=67J×2640N/m=0.21x=0.46m=46cm

Thus, the original compression of the spring = 46 cm

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Figure 8-73a shows a molecule consisting of two atoms of masses mand m(withm≪M) and separation r. Figure 8-73b shows the potential energy U(r)of the molecule as a function of r. Describe the motion of the atoms (a) if the total mechanical energy Eof the two-atom system is greater than zero (as isE1), and (b) if Eis less than zero (as isE2). For E1=1×10-19Jand r=0.3nm, find (c) the potential energy of the system, (d) the total kinetic energy of the atoms, and (e) the force (magnitude and direction) acting on each atom. For what values of ris the force (f) repulsive, (g) attractive, and (h) zero?

A70 kgfirefighter slides, from rest,4.3 mdown a vertical pole. (a) If the firefighter holds onto the pole lightly, so that the frictional force of the pole on her is negligible, what is her speed just before reaching the ground floor? (b) If the firefighter grasps the pole more firmly as she slides so that the average frictional force of the pole on her is500 Nupward, what is her speed just before reaching the ground floor?

In Fig. 8-25, a block slides along a track that descends through distance h. The track is frictionless except for the lower section. There the block slides to a stop in a certain distance Dbecause of friction. (a) If we decrease h, will the block now slide to a stop in a distance that is greater than, less than, or equal to D? (b) If, instead, we increase the mass of the block, will the stopping distance now be greater than, less than, or equal to D?

When a click beetle is upside down on its back, it jumps upward by suddenly arching its back, transferring energy stored in a muscle to mechanical energy. This launching mechanism produces an audible click, giving the beetle its name. Videotape of a certain click-beetle jump shows that a beetle of mass m=4.0×10-6kgmoved directly upward by 0.77 mm during the launch and then to a maximum heighth = 0.30 m. During the launch, what are the average magnitudes of (a) the external force on the beetles back from the floor and (b) the acceleration of the beetle in terms of g?

The luxury liner Queen Elizabeth 2 has a diesel-electric power plant with a maximum power of92 MWat a cruising speed of 32.5 knots. What forward force is exerted on the ship at this speed?(1 knot = 1.852 km / h).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.