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In Fig.8.52, a 3.5 kg block is accelerated from rest by a compressed spring of spring constant 640 N/m. The block leaves the spring at the spring’s relaxed length and then travels over a horizontal floor with a coefficient of kinetic friction μk=0.25.The frictional force stops the block in distance D = 7.8 m. What are (a) the increase in the thermal energy of the block–floor system (b) the maximum kinetic energy of the block, and (c) the original compression distance of the spring?


Short Answer

Expert verified

a) The increase in thermal energy of block-floor system 67 J

b) The maximum kinetic energy of the block-floor system 67 J

c) The original compression distance of the spring46 cm

Step by step solution

01

Listing the given quantities

The mass of the block,m=3.5kg

The spring constant of the spring,k=640N/m

The coefficient of friction,μk=0.25

The distance at which the blocks comes to rest,D=7.8m

02

Understanding the concept of conservation of energy

The total energy of the block-floor system is conserved during motion. The spring is initially compressed. When the block leaves the spring at its relaxed position, the potential energy is converted to kinetic energy of the block. As the block continues its motion, it loses its energy to the frictional force of the floor as it finally comes to rest.

Formula:

K.E=12mv2P.Espring=12kx2Eth=Ffx

03

Step 3(a): Calculation of increase in thermal energy of the block- floor system

The increase in thermal energy of the block-floor system occurs because of the friction between the block and the floor. Hence

Eth=FfxEth=μkmgD=0.25×3.5kg×9.8m/s2×7.8m=66.9J~67J

Hence, the increase in thermal energy of block-floor system = 67 J

04

Step 4(b): Calculation of maximum kinetic energy of block floor system

The block comes to rest after travelling distance D. Hence, the kinetic energy of the block at the start of this motion is completely converted to the thermal energy. So that we write

Eth=KE

Hence, the maximum kinetic energy of the block = 67 J

05

Step 5(c): Calculation of original compression of the spring

When the block leaves the spring, it is the relaxed position of the spring. So the kinetic energy of the block at this moment is potential energy of the compressed spring.

So we write,

K.Eblock=P.Espring12kx2=67J12×640N/m×x2=67Jx2=67J×2640N/m=0.21x=0.46m=46cm

Thus, the original compression of the spring = 46 cm

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