/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q11P (a) In Problem 5, what is the sp... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(a) In Problem 5, what is the speed of the flake when it reaches the bottom of the bowl? (b) If we substituted a second flake with twice the mass, what would its speed be? (c) If, instead, we gave the flake an initial downward speed along the bowl, would the answer to (a) increase, decrease, or remain the same?

Short Answer

Expert verified

a)v=2.08ms

b)v=2.08ms

c) Speed of the bowl at the bottom will increase.

Step by step solution

01

 Step 1: Given

Mass of ice flake,

m=2.0×10−3 k²µ

Radius,

(r)=0.22m

02

To understand the concept

The problem deals with the law of conservation of energy. The law of conservation of energy states that, total energy of an isolated system remains constant.

Formula:

Initialtotalenergy=Finaltotalenergy

03

(a) Calculate the speed of the flake when it reaches the bottom of the bowl

According to the law of conservation of energy:

KEi+PEi=KEf+PEf

12mv2+0=0+mgr

Hence,

v=(2gr)

v=2×0.22×9.8

v=2.08m/s

04

(b) Calculate the speed if we substituted a second flake with twice the mass

If the mass of flake is doubled, then there would be no change in speed, because the speed of flake doesn’t depend on the mass.

Hence,

v=2.08 m/s

05

(c) Figure out if the answer to (a) would increase, decrease, or remain the same if the flake is given an initial downward speed along the bowl

According to law of conservation of energy:

KEf=KEi+PEi−PEf

This indicates that if initial speed is greater, the final speed must increase.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A30 gbullet moving a horizontal velocity of500 m/scomes to a stop 12 cmwithin a solid wall. (a) What is the change in the bullet’s mechanical energy? (b) What is the magnitude of the average force from the wall stopping it?

A 2.0 kgbreadbox on a frictionless incline of angle θ=40°is connected, by a cord that runs over a pulley, to a light spring of spring constantk=120N/m, as shown in Figure. The box isreleased from rest when the spring is unstretched. Assume that the pulley is mass less and frictionless. (a) What is the speed of the box when it has moved 10 cmdown the incline? (b) How far down the incline from its point of release does the box slide before momentarily stopping, and what are the (c) magnitude (d) direction (Up or down the incline) of the box’s acceleration at the instant the box momentarily stops?

A1.50 kgsnowball is shot upward at an angle of34.0°to the horizontal with an initial speed of20.0 m/s.

  1. What is its initial kinetic energy?
  2. By how much does the gravitational potential energy of the snowball–Earth system change as the snowball moves from the launch point to the point of maximum height?
  3. What is that maximum height?

A 50 gball is thrown from a window with an initial velocity of 8.0 m/sat an angle of30°above the horizontal. Using energy methods, determine (a) the kinetic energy of the ball at the top of its flight and (b) its speed when it is 3.0 mbelow the window. (c)Does the answer to part (b) depend on either (c) the mass of the ball or (d) the initial angle?

Tarzan, who weighs 688 N , swings from a cliff at the end of a vine 18 m long (Figure). From the top of the cliff to the bottom of the swing, he descends by 3.2 m . The vine will break if the force on it exceeds 950 N . (a) Does the vine break? (b) If no, what is the greatest force on it during the swing? If yes, at what angle with the vertical does it break?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.