/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q7Q In a Compton-shift experiment, l... [FREE SOLUTION] | 91影视

91影视

In a Compton-shift experiment, light (in the x-ray range) is scattered in the forward direction, at=0 in Fig. 38-3. What fraction of the light鈥檚 energy does the electron acquire?

Short Answer

Expert verified

None of the fraction of light鈥檚 energy is acquired by the electron.

Step by step solution

01

Describe the change in wavelength in Compton Effect

The change in wavelength in Compton Effect is given by,

=hmc(1-cos)

Here,role="math" localid="1663133543883" is the Compton shift, h is the Planck鈥檚 constant, m is the mass of the electron, c is the speed of light, and is the scattering angle.

02

Find the fraction of the light’s energy does the electron acquire

Consider the following equation.

=hmc1-cos

Here,=0

=hmc1-cos0=hmc1-1=0

As =0, therefore, the change in wavelength is zero. So, there is no energy transferred to the electron.

Therefore, none of the fraction of light鈥檚 energy is acquired by the electron.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The following nonrelativistic particles all have the same kinetic energy. Rank them in order of their de Broglie wavelengths, greatest first: electron, alpha particle, neutron.

The wavelength of the yellow spectral emission line of sodium is 590nm. At what kinetic energy would an electron have that wavelength as its de Broglie wavelength?

Question:(a) Let n=a+ibbe a complex number, where aand barereal (positive or negative) numbers. Show that the product nn*is always a positive real number. (b) Let localid="1663080869595" m=c+idbe another complexnumber. Show that |nm=nm| .

Just after detonation, the fireball in a nuclear blast is approximately an ideal blackbody radiator with a surface temperature of about 1.0107K.

(a) Find the wavelength at which the thermal radiation is maximum and (b) identify the type of electromagnetic wave corresponding to that wavelength. This radiation is almost immediately absorbed by the surrounding air molecules, which produces another ideal blackbody radiator with a surface temperature of about 1.0105K.

(c) Find the wavelength at which the thermal radiation is maximum and (d) identify the type of electromagnetic wave corresponding to that wavelength.

The highest achievable resolving power of a microscope is limited only by the wavelength used; that is, the smallest item that can be distinguished has dimensions about equal to the wavelength. Suppose one wishes to 鈥渟ee鈥 inside an atom. Assuming the atom to have a diameter of 100pm, this means that one must be able to resolve a width of, say, 10pm.

(a) If an electron microscope is used, what minimum photon energy is required?

(b) If a light microscope is used, what minimum photon energy is required?

(c) Which microscope seems more practical? Why?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.