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Chapter 38: Q31P (page 1182)

What percentage increase in wavelength leads to a 75 % loss of photon energy in a photon-free electron collision?

Short Answer

Expert verified

300鈥�%

Step by step solution

01

Identification of the given data

The given data is listed below as-

There is a 75 % loss of photon energy

02

Significance of the momentum of a photon

The momentum of a photon is related to its energy and is given by-

p=Ec

Here, E is the rest energy of a photon which is given byE=mec2.

me Is the mass of electron and is the speed of light.

03

To find the percentage increase in wavelength

Let E is the energy of photon initially andE'is the energy of photon after collision. The fractional energy loss is given by-

螖EE=E鈭�E'E=螖位位+螖位

Now,

螖位位=螖E/E1鈭�螖E/E=0.751鈭�0.75=3=300鈥�%

Thus, the percentage increase in wavelength is 300鈥�%.

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