91影视

The rate of arrival of solar energy is given by, P = IA鈥︹��. (1)

Here, I is the intensity, and A is the area.

The energy Eof a photon of wavelength $位$is given by,

$E=\frac{hc}{位}$鈥︹��. (2)

Here, h is the Planck鈥檚 constant, and c is the speed of light.

(a)

Substitute the below values in eq 1.

$$\begin{gathered} \mathrm{I}=1.39\mathrm{kW}/{\mathrm{m}}^2 \\ \mathrm{A}=2.50{\mathrm{m}}^2 \end{gathered}$$

$$\begin{gathered} \mathrm{P}=\left(1.39\mathrm{kW}/{\mathrm{m}}^2\right)\left(2.60{\mathrm{m}}^2\right) \\ =3.61\mathrm{kW} \end{gathered}$$

Therefore, the rate of arrival of solar energy is 3.61 kW.

(b)

Substitute the below values in eq. 2. to calculate the energy of the photon.

$$\begin{gathered} \mathrm{位}=550\mathrm{nm} \\ \mathrm{J}=6.626脳{10}^{-34}\mathrm{J}.\mathrm{s} \\ \mathrm{c}=3脳{10}^8\mathrm{m}/\mathrm{s} \end{gathered}$$

The expression to calculate the rate at which solar photons are absorbed is given by,

$R=\frac{P}{E}$ ...(3)

Substitute the below values in eq 3.

Therefore, the rate of absorption of photon by panel is$1.00脳{10}^{22}\mathrm{photons}/\mathrm{s}.$

(c)

The expression to calculate the time taken by the mole of photons to be absorbed by the panel is given by,

$t=\frac{N_A}{R}$ ...(4)

Substitute the below values in eq 4.

$$\begin{gathered} \mathrm{R}=1.00脳{10}^{22}\mathrm{photons}/\mathrm{s} \\ {\mathrm{N}}_{\mathrm{A}}=6.02脳{10}^{23}\mathrm{photons} \end{gathered}$$

Therefore, the required time is 60.2 s.