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The acceleration of a (t) particle undergoing SHM is graphed in Fig. 15-21. (a) Which of the labeled points corresponds to the particle at-xm? (b) At point 4, is the velocity of the particle positive, negative, or zero? (c) At point5, is the particle at -xm, or at +xm, at 0, between and, or between 0 and +xm?

Short Answer

Expert verified
  1. Point 2 corresponds to the particle at -xm.
  2. The velocity of particle is positive at point 4
  3. The particle is between 0 at xmat point 5.

Step by step solution

01

The given data 

The graph of acceleration versus time for a particle undergoing SHM is given.

02

Understanding the concept of SHM of a particle

From the given graph, we can determine the position of the particle. We use the direction of acceleration according to the position of the particle. The velocity of the particle is positive, negative or zero can be determined from it.

Formula:

The acceleration of the body in SHM, a=-2x (i)

03

Step 3: Calculation of the point that corresponds to the particle at -xm

a)

We know that in acceleration, SHM is always negative corresponding equation (i). When the particle moves away from mean position and acceleration is positive, the particle moves towards mean position.

Here particle is at point 2; acceleration is positive that is the particle is moving toward mean position. Also, the acceleration has maximum value at point 2.

Hence, point 2 corresponds to the particle at -xm.

04

Calculation for the velocity at point 4

b)

At point 4, the particle is at mean position because acceleration is zero. It came from -xmand is moving towards +xmso the velocity is positive.

05

Calculation of the position of particle at point 5

c)

At point 5, the particle is moving from mean position towards+xmand having negative acceleration.

Hence the particle is between 0 and + xm.

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Most popular questions from this chapter

You are to build the oscillation transfer device shown in Fig.15-27. It consists of two spring鈥揵lock systems hanging from a flexible rod. When the spring of system is stretched and then released, the resulting SHM of system at frequency oscillates the rod. The rod then exerts a driving force on system 2, at the same frequency f1. You can choose from four springs with spring constants k of 1600,1500,1400, and 1200 N/m, and four blocks with masses m of 800,500,400, and 200 kg. Mentally determine which spring should go with which block in each of the two systems to maximize the amplitude of oscillations in system 2.

If the phase angle for a block鈥搒pring system in SHM is /6and the block鈥檚 position is given bylocalid="1655098514909" x=xmcos(蝇t/), what is the ratio of the kinetic energy to the potential energy at timet=0?

In Fig. 15-59, a solid cylinder attached to a horizontal spring (k=3.00 N/m) rolls without slipping along a horizontal surface. If the system is released from rest when the spring is stretched by 0.250 m , find (a) the translational kinetic energy and (b) the rotational kinetic energy of the cylinder as it passes through the equilibrium position. (c) Show that under these conditions the cylinder鈥檚 center of mass executes simple harmonic motion with period T=23M2k where M is the cylinder mass. (Hint: Find the time derivative of the total mechanical energy.)

Two particles oscillate in simple harmonic motion along a common straight-line segment of length A. Each particle has a period of 1.5s , but they differ in phase by 6rad.

  1. How far apart are they (in terms ofA ) 0.5safter the lagging particle leaves one end of the path?
  2. Are they then moving in the same direction, toward each other, or away from each other?

For a simple pendulum, find the angular amplitude mat which the restoring torque required for simple harmonic motion deviates from the actual restoring torque by1.0%. (See 鈥淭rigonometric Expansions鈥 in Appendix E.)

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