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Figure (a)is a partial graph of the position function x(t)for a simple harmonic oscillator with an angular frequency of 1.20鈥塺补诲/s ; Figure (b) is a partial graph of the corresponding velocity function v(t). The vertical axis scales are set by xs=5.0cm and vs=5.0鈥塩尘/s. What is the phase constant of the SHM if the position function x(t)is in the general form x=xmcos(t+)?

Short Answer

Expert verified

The phase constant of the SHM, if the position function x(t)is in the formx(t)=xmcos(t+f) , is 0.695鈥塺补诲.

Step by step solution

01

Stating the given data

  1. Angular frequency of the harmonic oscillator, =1.20鈥塺补诲/s
  2. Vertical axis scale values,xs=5.0鈥塩尘/s and.vs=5.0鈥塩尘/s
02

Understanding the concept of simple harmonic motion

Using the formula of velocity function and position function, we can find the phase constant of SHM by taking the ratio of velocity and position functions.

Formulae:

The general expression for velocity of motion,x=xmcos(t+f) (i)

The general expression for velocity of motion, v=xmsin(t+f) (ii)

03

Calculation of phase constant

Dividing equations(ii) by (i), we get

v(t)x(t)=xmsin(t+f)xmcos(t+f)

At
t=0鈥塻,v0=5鈥塩尘/s,x0=5鈥塩尘

v0x0=sin(f)cos(f)v0x0=tanff=tan1v0x0=tan1[(5鈥塩尘/s)(1.20rad/s)(5鈥塩尘)]=0.695鈥塺补诲

Therefore,the phase constant of the SHM, if the position functionsx(t)is in the form

x(t)=xmcos(t+f), is 0.695鈥塺补诲.

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