91影视

A nuclear reaction is given:${}^{238}\mathrm{U}鈫�{}^4\mathrm{He}+{}^{234}\mathrm{Th}$

Electric potential energy is the energy that is needed to move a charge against an electric field. The energy required to move the electron from any surface is less hard in comparison to the energy required to move it from a strong electric field. Thus, stronger field gives larger energy.

Formula:

The electrostatic potential energy of a system of charges,$鈭�\left(r\right)=\frac{k{q}_1{q}_2}{r}鈥�........\left(1\right)$

Equation (1) gives the electrostatic potential energy between two uniformly charged spherical charges (in this case $q_1=2e$and$q_1=90e$ ) with rbeing the distance between their centers. Assuming the 鈥渦niformly charged spheres鈥� condition is met in this instance, we write the equation in such a way that we can make use of$K=1/4{\mathrm{蟺蔚}}_0$and the electron-volt unit as follows:

$$\begin{gathered} U\left(r\right)=\frac{\left(9脳{10}^{9}N.m^2/C^2\right)\left(2脳1.6脳{10}^{-19}C\right)\left(90e\right)}{r} \\ =\frac{2.59脳{10}^{-7}}{r}eV \end{gathered}$$

with runderstood to be in meters. It is convenient to write this for rin femtometers, in this case U = (259/r)MeV. This is plotted below.

Hence, the graph for electrostatic potential energy versus the distance between the particles is plotted.