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A purse at radius 2.00 m and a wallet at radius 3.00 m travel in uniform circular motion on the floor of a merry-go-round as the ride turns. They are on the same radial line. At one instant, the acceleration of the purse is (2.00m/s2)i^+(4.00m/s2)j^.At that instant and in unit-vector notation, what is the acceleration of the wallet?

Short Answer

Expert verified

The acceleration of the wallet is a→w=(3.00m/s2)i^+(6.00m/s2)j^

Step by step solution

01

Given

  1. The radius of the purse isrp=2.00m
  2. The radius of the wallet isrw=3.00m
  1. The acceleration of the purse is, a=(2.00m/s2)i^+(4.00m/s2)j^
02

Understanding the concept of circular motion

A purse and wallet travel in a uniform circular motion. They are on the same radial line; hence the angular frequency of the purse and wallet is the same. Both have centripetal acceleration only.

Formula:

a=Ó¬2r

03

Calculate the acceleration of the wallet

The purse and the wallet are performing uniform circular motion. The radius of purse -rPand radius of the wallet -rware acting along the same line; hence their angular velocity isthesame.

The equation of acceleration of purse is

aP=Ó¬2rP …(¾±)

The equation of acceleration of wallet is

aw=Ó¬2rw …(¾±¾±)

Dividing equation (ii) by (i),

awap=rwrpaw=rwrpawaw→=32((2.00m/s2)i^+(4.00m/s2)j^)=(3.00m/s2)i^+(6.00m/s2)j^

Therefore, the acceleration of the wallet is (3.00m/s2)i^+(6.00m/s2)j^.

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