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Figure 4-22 shows the initial position i and the final position f of a particle. What are the (a) initial position vectorr1→and (b) final position vectorrf→, both in unit-vector notation? (c) What is the x component of displacement∆r→?

Short Answer

Expert verified

a) Initial position vectorri→=7iÁåœ+jÁåœ-2kÁåœ

b) Final position vector rf→=5iÁåœ-3jÁåœ+kÁåœ

c) The x component of displacement∆r→=-2iÁåœ

Step by step solution

01

Given information

rix=7 mriy=1 mriz=-2 mrfx=5 mrfy=-3 mrfz=1 m

02

To understand the concept

Vector can be written by measuring the distances along each direction. Displacement can be calculated by change in position between two vectors.

Formulae:

Unit vector notation

r→=rxiÁåœ+ryjÁåœ+rzkÁåœ

03

(a) To find initial position vector r1→

Initial position vector r1→

r1→=rixiÁåœ+riyjÁåœ+rizkÁåœr1→=7iÁåœ+jÁåœ-2kÁåœ

04

(b) To find initial position vector rf→

rf→=rfxiÁåœ+rfyjÁåœ+rfzkÁåœrf→=5iÁåœ-3jÁåœ+kÁåœ

05

(c) To find x component of displacement ∆r→

We have, displacement vector is given by:

∆r→=rf→-ri→=5-7iÁåœ+-3-1jÁåœ+1--2kÁåœ=-2iÁåœ-4jÁåœ+3kÁåœ

Hence,

The x component of the displacement is ∆r→=-2iÁåœ.

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