91Ó°ÊÓ

1. Speed of car,$v=12.0\mathrm{m}/\mathrm{s}$
2. Acceleration of car,role="math" localid="1657010443923" $a=3.0\mathrm{m}/{\mathrm{s}}^2$

If a particle travels along a circle or circular arc of radius r at constant speed v, it is said to be in a uniform circular motion and has an acceleration $\stackrel{→}{\mathrm{a}}$of constant magnitude. The direction of$\stackrel{→}{\mathrm{a}}$ is toward the center of the circle or circular arc, and is said to be centripetal acceleration.

We can use the centripetal acceleration equation to find the distance of the car from the center of the circle and we know the acceleration of the car is the centripetal acceleration.

Formulae:

The acceleration of the body in centripetal motion,$a=\frac{v^2}{r}$ (i)

Where a is the centripetal acceleration, v is the speed, r is the radius of curvature

The left side figure is for a clockwise motion.

Hence acceleration and distance from the centre is same for both cases. And the value of distance is given using equation (i) as:

$r=\frac{v^2}{a}$

Substitute the $12\mathrm{m}/\mathrm{s}$ for v, and $3\mathrm{m}/{\mathrm{s}}^2$ for a in the above equation.

$$\begin{gathered} =\frac{{(12.0\mathrm{m}/\mathrm{s})}^2}{3.00\mathrm{m}/{\mathrm{s}}^2} \\ =48\mathrm{m} \end{gathered}$$

For clockwise motion, the distance of the car from the centre is 48 m and the direction of the car is towards the west.

The right-side figure is for counter-clockwise motion. Hence acceleration and distance from the center are the same in both cases.

Hence, for counter-clockwise motion, the distance of the car from the centre is 48m and the direction of the car is towards the west.