91Ó°ÊÓ

The velocity of the automobile for the first 40 km,v₁ = 30 km/hr.

The velocity of the automobile for the second 40 km, v₂ = 60 km/hr. .

The total displacement,$∆x=80$ .

Average velocity can be found by dividing the total displacement by total time, while average speed can be found by dividing the total distance by total time.

The expression for the average velocity is calculated as follows:

$v_{avg}=\frac{∆x}{∆t}$ (i)

Here,$∆x$ is the total displacement, and$∆t$ is the time duration.

The expression for the average speed is as follows:

$s_{avg}=\frac{Totaldis\tan ce}{∆t}$

Since the total distance is traveled in two parts, the total time taken is the sum of the time taken in each part of the journey.

$$\begin{gathered} ∆t=∆t_1+∆t_2 \\ =\frac{40km}{30km/hr}+\frac{40km}{60km/hr} \\ =2h \end{gathered}$$

The average velocity is as follows:

.$$\begin{gathered} v_{avg}=\frac{∆x}{∆t} \\ =\frac{80km}{2h} \\ =40km/h \end{gathered}$$

Therefore, the average velocity of the automobile is 40 km/h .

Since the automobile travels in a straight line towards the positive x-direction, the total distance traveled is equal to the total displacement.

. Total distance =80 km

The average speed is calculated as follows:

$$\begin{gathered} S_{avg}=\frac{Totaldis\tan ce}{∆t} \\ =\frac{80km}{2h} \\ =40km/h \end{gathered}$$

Therefore, the average speed of the automobile is 40 km/h .

You can plot displacement vs time as shown in the figure below. Two different paths are indicated by a blue line. The slope of the first path will give the velocity of 30 km/hr, and the slope of the second path will give the velocity of 60 km/hr. The slope of the black line will give the average velocity.