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Figure depicts the motion of a particle moving along an x axis with a constant acceleration. The figure鈥檚 vertical scaling is set byxs=6.0m. What are the (a) magnitude and(b) direction of particle鈥檚 acceleration?

Short Answer

Expert verified

a) The magnitude of the acceleration is 4.0m/s2.

b) The acceleration vector points in the +xdirection.

Step by step solution

01

Finding the relationship between Vo and a

The kinematic equations related the initial velocity, final velocity, acceleration, displacement, and time to each other.Use these equations to find the linear relationship between initial velocity and acceleration. It is given that, xs=6.0m.

Using the second equation of motion,

x-xo=vot+12at2

From figure, x=0.0matt=1.0s.

localid="1656149026288" 0--2=vo1+12a12

2=vo+12a(i)

Also, x=6.0matt=2.0sat

6--2=vo2+12a22

4=vo+a (ii)

02

(a) Calculating the magnitude of acceleration

Simultaneously solving equation (i) and (ii,

vo=0m/s

a=4.0m/s2 (iii)

Therefore, the magnitude of acceleration is 4.0m/s2.

03

(b) Finding the direction of acceleration

The acceleration found in equation (iii) is positive. Therefore, acceleration is directed in the+x direction.

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