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Chapter 2: Q32P (page 34)

A world鈥檚 land speed record was set by Colonel John P. Stapp when in March 1954, he rode a rocket propelled sled that moved along a track at1020km/h. He and the sled were brought to a stop in1.4sec. In terms of g, what acceleration did he experience while stopping?

Short Answer

Expert verified

Acceleration in terms of gis21g

Step by step solution

01

Given information

v=1020km/ht=1.4s

02

Concept and formula used in the given question

The problem deals with the simple physical quantity acceleration which refers to the rate at which the velocity changes. Using the velocity and given time in standard notation, the acceleration can be found. And by dividing it bythe value of 鈥済,鈥� the acceleration in terms of 鈥済鈥� can be determined. To initiate, all the quantities should be converted to the standard units.

Formula:

The acceleration in general is given by,

a=vt

03

To calculate acceleration in terms of g

To find acceleration, first convert1020km/h intom/s

1=kmh=10003600m/s1020kmh脳10003600ms脳h1km=283.33m/sv=283.33m/s

Using equation (i),

a=vt-283.331.4=202.4m/s2

Acceleration in terms of g,

a=202.49.81=21gm/s2

Thus, the acceleration in terms ofgis21g

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