91Ó°ÊÓ

The coverage of paint is $460{\mathrm{ft}}^2\mathrm{per}\mathrm{gallon}$.

Chain-link conversions are used for unit conversion in which given values are multiplied successively by conversion factors.

1 ft = 0.3048 m

$1\mathrm{gal}=231{\mathrm{inch}}^3\mathrm{and}1{\mathrm{inch}}^3=1.639×{10}^{-2}\mathrm{L}$

Therefore,

1 gal = 3.79 L

Thus,

$$\begin{gathered} \frac{\left[460×(0.{3048}^2\right]}{3.79}=11.275 \\ ≈11.3\frac{{\mathrm{m}}^2}{\mathrm{L}} \end{gathered}$$

Thus, the quantity $460f{t}^2/gal$becomes $11.3{\mathrm{m}}^2/\mathrm{L}$.

The conversion factor is$1m^3=1000L$

Thus, the quantity $460f{t}^2/gal$becomes,

$11.3\frac{m^2}{L}×\frac{1000L}{1m^3}=1.13×{10}^4{m}^{-1}$

Thus, the quantity $460f{t}^2/gal$is equal to $1.13×{10}^4{m}^{-1}$.

The inverse of$460f{t}^2/gal$is calculated as,

$\frac{1}{460f{t}^2/gal}=2.17×{10}^{-3}gal/f{t}^2$

Thus, the inverse of is $460f{t}^2/gal\mathrm{is}2.17×{10}^{-3}gal/f{t}^2$.

Since the volume of the paint is to be used to paint the unit area, it is possible to find the thickness of the paint. It is also possible to determine the amount of paint required to paint a certain area with the specified thickness.