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Two plates (as in Fig. 32-7) are being discharged by a constant current. Each plate has a radius of 4.00cm. During the discharging, at a point between the plates at radial distance 2.00cmfrom the central axis, the magnetic field has a magnitude of12.5nT . (a) What is the magnitude of the magnetic field at radial distance6.00 ? (b) What is the current in the wires attached to the plates?

Short Answer

Expert verified
  1. The magnitude of the magnetic field at radial distance6.00cm is 16.7nT.

Step by step solution

01

Listing the given quantities: 

Radius of plates R=0.04m

Radial distance,r1=0.02m

Radial distance, r2=0.06m

Magnetic field, B1=12.5109T

02

Understanding the concepts of magnetic field:

This magnetic field increases from the center of the capacitor to a maximum value at the edges of the capacitor and then begins to decrease again as we move away from the capacitor.

Formulas:

The magnetic field inside the plates:B1=0id2蟺搁2r1

The magnetic field outside the plates:B2=0id2蟺谤2

Here, B1 and B2 are the magnetic field inside and outside the plates respectively, id is the fictitious current, R is the radius of the plate, r1 and r2 are the radial distance, and 0 is the permeability of free space having a value of 4107N/A2.

03

(a) Calculations of the magnitude of magnetic field at radial distance  6.00 cm:

The point at the radial distance of r1is between the plates; the magnetic field at the point is given by,

B1=0id2蟺搁2r112.5109T=0id2蟺搁2r1

Rearrange the above equation as below.

0id2=(12.5109T)R2r1=(12.5109T)(0.04m)20.02m

0id2=109Tm

鈥.. (1)

Now the point at a radial distance ofr2is outside the plates. So the magnetic field at that point is,

B2=0id2蟺谤2=10.06m(109Tm)=16.7109T=16.7nT

Hence, the magnitude of magnetic field at radial distance 6.00cm is 16.7nT.

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