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The orbital magnetic dipole is $m_l=3$.

The orbital magnetic dipole is $m_l=4$.

You have the formula for orbital magnetic dipole moment. From the given data, you can get the required value.

Formula:

The orbital magnetic dipole moment equation is,

${渭}_{orb}=鈭�m_l{渭}_B$

Here, ${渭}_B$is the magnetic moment having a value of $9.27脳{10}^{鈭�24}\raisebox{1ex}{$\text{J}$}\!\left/ \!\raisebox{-1ex}{$\text{T}$}\right.$.

First take the orbital magnetic dipole as,

$m_l=3$

So, the orbital magnetic dipole moment will be,

$\begin{array}{rcl}{渭}_{orb}& =& 鈭�m_l{渭}_B\\ & =& 鈭�3脳(9.27脳{10}^{鈭�24}\raisebox{1ex}{$\text{J}$}\!\left/ \!\raisebox{-1ex}{$\text{T}$}\right.\\ & =& 鈭�2.78脳{10}^{-23}\raisebox{1ex}{$\text{J}$}\!\left/ \!\raisebox{-1ex}{$\text{T}$}\right.\end{array}$

Hence, the component of the orbital magnetic dipole moment of an electron with the values $m_l=3$ will be $鈭�2.78脳{10}^{鈭�23}\raisebox{1ex}{$\text{J}$}\!\left/ \!\raisebox{-1ex}{$\text{T}$}\right.$.

Take $m_l=鈭�4$.

Thus, the orbital magnetic dipole moment is,

$\begin{array}{rcl}{渭}_{orb}& =& 鈭�m_l{渭}_B\\ & =& 鈭�(鈭�4)脳\left(9.27脳{10}^{鈭�24}\raisebox{1ex}{$\text{J}$}\!\left/ \!\raisebox{-1ex}{$\text{T}$}\right.\right)\\ & =& 3.71脳{10}^{-23}\raisebox{1ex}{$\text{J}$}\!\left/ \!\raisebox{-1ex}{$\text{T}$}\right.\end{array}$

Hence, the component of the orbital magnetic dipole moment of an electron with the values $m_l=鈭�4$will be $\begin{array}{rcl}& & 3.71脳{10}^{-23}\raisebox{1ex}{$\text{J}$}\!\left/ \!\raisebox{-1ex}{$\text{T}$}\right.\end{array}$.