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a) In Checkpoint 5, if the dipole moment is rotated from orientation 2 to orientation 1 by an external agent, is the work done on the dipole by the agent positive, negative, or zero?

(b) Rank the work done on the dipole by the agent for these three rotations, greatest first.21,24,23

Short Answer

Expert verified
  1. Work that agent did is positive.
  2. .W21=W24>W23

Step by step solution

01

Step 1: Given

Four orientations of magnetic dipole moments in the given magnetic field.

02

Determining the concept

Use the relation of work done with the potential energy of a magnetic dipole and find the work done for different orientations of the dipole. From its sign, determine whether it is positive or negative.

The work done is given as-

W=U=.B

Where W is work done, U is potential energy,B is magnetic field, and 饾渿 is magnetic dipole moment.

03

(a) Determining the work done on the dipole by the agent is positive, negative or zero

The work done on the dipole appears as the change in potential energy. The work done in rotating magnetic dipole of magnitude,due to magnetic field of magnitude, from initial orientationitofis given by,

Wa=U=UfUiWa=Bcosf(Bcosi)

Wa=BcosiBcosf

Wa=B(cosicosf).(1)

In orientation 2,i=and in orientation 1

Substituting this values in 1),f=(180i)

Wa=B(coscos(180))

Wa=B(cos+cos)

Wa=2Bcos

Since is less than 90, cosis greater than zero.

So, the work done is positive.

Hence,the work done is positive.

04

(b) Determining the rank of the work done on the dipole by the agent for three rotations 2→1,2→4,2→3

Work done for three rotations 21,24,23:

Work done in rotation21isW21=2Bcos,

Work done in rotation from24is,

i=andf=(180+)

Substituting in equation 1),

Wa=B(coscos(180+))

Wa=B(cos(cos))

Wa=2Bcos

Work done in rotation from 23is,

i=andf=(360)

Wa=B(coscos(360))

cos(360)=cos360*cos+sin360*sin

cos(360)=cos

Substituting in 1),

Wa=B(coscos(360))

Wa=B(coscos)

Wa=0

Hence,the ranking for the three cases isW21=W24>W23.

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