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A proton, a deuteron (q=+e,m=2.0u), and an alpha particle (q=+2e,m=4.0u) all having the same kinetic energy enter a region of uniform magnetic field, moving perpendicular to it. What is the ratio of (a) the radius rd of the deuteron path to the radius rpof the proton path and (b) the radius rof the alpha particle path to rp?

Short Answer

Expert verified

a) Ratio of the radius rdof the deuteron path to the radius rp of the proton path,rdrp=1.4

b) Ratio of the radius rof the alpha particle path to the radius rpof the proton path,rrp=1.0

Step by step solution

01

Identification of given data

  1. Mass of proton,mp=1u
  2. Charge of proton,qp=+e
  3. Mass of deuteron,md=2u
  4. Charge of deuteron,qd=+e
  5. Mass of particle, m=4u
  6. Charge of particle,q=+2e
02

 Step 2: Understanding the concept

For a charge circulating in a magnetic field, the centripetal force is provided by magnetic force. By using this concept, we can find the radius of the circular path of each particle and then the required ratios.

Formula:

  1. Magnetic force,FB=qvB
  2. Centripetal force,F=(mv2)/r
03

Step 3: (a) Determining the ratio of the radius rd of the deuteron path to the radius rp of the proton path  

For a charge circulating in a magnetic field, centripetal force is provided by the magnetic force.

Magnetic force

FB=qvB 鈥(颈)

Centripetal force

F=(mv2)/r 鈥(颈颈)

Equating equation (i) and (ii),

qvB=(mv2)/r

Rearranging the equation for radius rr=mvqB

鈥(颈颈颈)

Kinetic energy of the circulation particle is given by

K=12mv2

v=2Km

Using in equation (iii), we get

r=mqB2Km

r=mq2KB 鈥(颈惫)

It is given that the magnetic force and kinetic energy of each particle is the same. Applying equation (iv) to deuteron and proton, we get

rd=mdqd2KB

rp=mpqp2KB

Taking ratio rd of rp,

rdrp=mdqdqpmp

Using all the given values, we get

rdrp=2+e+e1

rdrp=1.414

Ratio of the radius rd of the deuteron path to the radius rpof the proton path:

rdrp=1.414~1.4

04

(b) Determining the ratio of the radius rα of the alpha particle path to rp   

It is given that magnetic force and kinetic energy of each particle is the same. Applying equation (iv) toparticle and proton, we get

r=mq2KB

rp=mpqp2KB

Taking ratio of randrp:

rrp=mqqpmp

Using all the given values, we get

rdrp=4+2e+e1

Ratio of the radius rof the alpha particle path to the radius rp. of the proton path:

rrp=1.0

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