/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q65P A wire of length 25.0cm carrying... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A wire of length 25.0cm carrying a current of 4.51mAis to be formed into a circular coil and placed in a uniform magnetic fieldB→of magnitude 5.71mT. If the torque on the coil from the field is maximized. What are (a) the angle between B→and the coil’s magnetic dipole moment? (b) the number of turns in the coil? (c) What is the magnitude of that maximum torque?

Short Answer

Expert verified
  1. The angle between B→and the coil’s magnetic dipole moment is localid="1663952997688" θ=90∘.
  2. The number of turns in the coil is N=1.
  3. The magnitude of the maximum torque is τmax=1.28×10-7N.m.

Step by step solution

01

Given

The length of the wire is L=25.0cm=0.25m.

The current in the coil is i=4.51mA=4.51×10-3A.

The magnitude of magnetic field is B=5.71mT=5.71×10-3T.

02

Understanding the concept

By taking cross product of magnetic moment vector and magnetic field vector, we can find the angle between B→and the coil’s magnetic dipole moment when the torque is maximized. By finding the equation of radius rof coil in the form of length of the wire and substituting it in the formula for themagnetic moment, we can find the number of turns in the coil whenthemagnetic moment ismaximized. We can find the magnitude of the maximum torque by using its formula.

Formula:

The torque is given byτ⃗=μ⃗×B⃗

The length of wire isL=N(2Ï€r)

The magnitude of the magnetic moment isμ=NiA

The magnitude of the maximum torque is given byτmax=μB

03

(a) Calculate the angle between B→ and the coil’s magnetic dipole moment 

We know that torque is given by

τ→=μ→×B→τ→=μBsinθ

The torque is maximum when θ=90∘

Therefore, when the torque is maximized, the angle between B→and coil’s magnetic dipole moment is θ=90∘

04

(b) Calculate the number of turns in the coil

The length of wire isL=N(2Ï€r)

Where N is the number of turns of the coil,2Ï€°ùis the circumference of the coil.

Therefore, the radius is

r=L2Ï€Nâ‹…â‹…â‹…â‹…â‹…â‹…(1)

The magnitude of the magnetic moment is

μ=NiA

But, area A=Ï€°ù2, therefore,

μ=Niπr2

From equation (1), we get,

μ=NiÏ€L2Ï€±·2

role="math" localid="1662961462302" μ=(L2i)4Ï€±·â‹…â‹…â‹…â‹…â‹…â‹…(2)

Thus the torque becomes,

τ→=μB=(L2iB)4Ï€±·

Thus, to maximize the torque, the number of turns N should be minimum.

So, the number of turns N=1.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Fig. 28-49 shows a current loop ABCDEFAcarrying a current i= 5.00 A. The sides of the loop are parallel to the coordinate axes shown, with AB= 20.0 cm, BC= 30.0 cm, and FA= 10.0 cm. In unit-vector notation, what is the magnetic dipole moment of this loop? (Hint:Imagine equal and opposite currents iin the line segment AD; then treat the two rectangular loops ABCDA and ADEFA.)

Figure 28-23 shows a wire that carries current to the right through a uniform magnetic field. It also shows four choices for the direction of that field.

(a) Rank the choices according to the magnitude of the electric potential difference that would be set up across the width of the wire, greatest first.

(b) For which choice is the top side of the wire at higher potential than the bottom side of the wire?

A proton of charge +eand mass menters a uniform magnetic field B⃗=Bi^ with an initial velocityv⃗=v0xi^+v0yj^.Find an expression in unit-vector notation for its velocity at any later time t.

In a nuclear experiment a proton with kinetic energy 1.0 MeV moves in a circular path in a uniform magnetic field.

(a)What energy must an alpha particle ( q=+2e,m=4.0 u)

(b)What energy must a deuteron (q=+e,m=2.0 u ) have if they are to circulate in the same circular path?

A positron with kinetic energy2.00keV is projected into a uniform magnetic field B→of magnitude 0.100T, with its velocity vector making an angle of 89.0° with.

(a) Find the period.

(b) Find the pitch p.

(c) Find the radius rof its helical path.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.