/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q28P During spring semester at MIT, r... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 7: Q28P (page 172)

During spring semester at MIT, residents of the parallel buildings of the East Campus dorms battle one another with large catapults that are made with surgical hose mounted on a window frame. A balloon filled with dyed water is placed in a pouch attached to the hose, which is then stretched through the width of the room. Assume that the stretching of the hose obeys Hooke鈥檚 law with a spring constant of 100 N/m. If the hose is stretched by 5.00 m and then released, how much work does the force from the hose do on the balloon in the pouch by the time the hose reaches its relaxed length?

Short Answer

Expert verified

The work by the hose on the balloon is Ws=1250J

Step by step solution

01

Given data

  1. The spring constant of the hose is,k=100N/m .
  2. The maximum elongation of the hose is,xi=5.00m.
  3. The final position of the hose is, xf=0m.
02

Understanding the concept

We can use the concept of work done by the spring on the block.

Formulae:

Ws=12kxi2-12kxf2

03

Calculate how much work the force from the hose does on the balloon

Work energy theorem states that change in the kinetic energy of the system will be equal to the work done of the system.

The work by the spring is,

Ws=12kxi2-xf2

Substitute the values in the above expression, and we get,

Ws=12脳100N/m脳5.00m2-0m2Ws=12脳100脳5.0021N/m脳1m2脳1J1N路mWs=1250J

Thus, the work by the hose on the balloon is Ws=1250J.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Figure 7-21ashows four situations in which a horizontal force acts on the same block, which is initially at rest. The force magnitudes are F2=F4=2f1=2F3. The horizontal component vXof the block鈥檚 velocity is shown in figure 7-21bfor the four situations. (a) Which plot in figure 7-21b best corresponds to which force in fig. 7-21a? (b) Which plot in figure 7-21c (for kinetic energy K versus time t) best corresponds to which plot in fig. 7-21b ?

Figure 7-28shows three forces applied to a trunk that moves leftward by 3.00 m over a frictionless floor. The force magnitudes are F1=5.00N, F2=9.00N, and F3=3.00N, and the indicated angle is 胃=60.0掳. During the displacement, (a) what is the net work done on the trunk by the three forces and (b) does the kinetic energy of the trunk increase or decrease?

A cave rescue team lifts an injured spelunker directly upward and out of a sinkhole by means of a motor-driven cable. The lift is performed in three stages, each requiring a vertical distance of 10.0鈥�m: (a) the initially stationary spelunker is accelerated to a speed of 5.00鈥�m/s; (b) he is then lifted at the constant speed of5.00鈥�m/s ; (c) finally he is decelerated to zero speed. How much work is done on the 80.0鈥�鈥�kgrescuee by the force lifting him during each stage?

To push a 25.0 kg crate up a frictionless incline, angled at 25.0掳to the horizontal, a worker exerts a force of 209 N parallel to the incline. As the crate slides1.50 m, how much work is done on the crate by (a) the worker鈥檚 applied force, (b) the gravitational force on the crate, and (c) the normal force exerted by the incline on the crate? (d) What is the total work done on the crate?

The only force acting on a 2.0 kg canister that is moving in an xy plane has a magnitude of 5.0 N. The canister initially has a velocity of 4.0 m/sin the positive x direction and sometime later has a velocity of 6.0 m/sin the positive y direction. How much work is done on the canister by the 5.0 N force during this time?
See all solutions

Recommended explanations on Physics Textbooks

Electricity

Read Explanation

Force

Read Explanation

Translational Dynamics

Read Explanation

Waves Physics

Read Explanation

Wave Optics

Read Explanation

Solid State Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.