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A double-convex lens is to be made of glass with an index of refraction of 1.5.One surface is to have twice the radius of curvature of the other and the focal length is to be 60mm. What is the (a) smaller and (b) larger radius?

Short Answer

Expert verified
  1. Smaller radius of the lens is 45mm
  2. Larger radius of the lens is 90mm

Step by step solution

01

Listing the given quantities

Refractive index of lens, n=1.5

Focal length,f=60.0mm

Radius of one surface is twice the other, i.e.,r2=-2r1

02

Understanding the concepts of lens maker equation

By using the Lens maker’s formula, we can find the radius of both curvatures of the lens.

Formula:

Lens maker’s formula

1f=(n-1)(1r1-1r2)...34-10

03

(a) Calculations of the smaller radius of the lens

Lens maker’s formula is given by equation,

1f=n-11r1-1r2

Since one surface has twice the radius of the other and since one surface is convex to the incoming light while the other is concave, we can write,

r2=-2r1

So, we can get,

1fn-1=1r1+12r1=32r1r1=32fn-1=1.560.01.5-1=45mm

Smaller radius of the lens is 45mm.

04

(b) Calculations of the larger radius of the lens

As per the condition given in the problem, r2will be double of r1

So, r2 = 90 mm

Larger radius of the lens is 90 mm

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Most popular questions from this chapter

The equation 1p+1i=2rfor spherical mirrors is an approximation that is valid if the image is formed by rays that make only small angles with the central axis. In reality, many of the angles are large, which smears the image a little. You can determine how much. Refer to Fig. 34-22 and consider a ray that leaves a point source (the object) on the central axis and that makes an angle a with that axis. First, find the point of intersection of the ray with the mirror. If the coordinates of this intersection point are x and y and the origin is placed at the center of curvature, then y=(x+p-r)tan a and x2+ y2= r2where pis the object distance and r is the mirror’s radius of curvature. Next, use tanβ=yxto find the angle b at the point of intersection, and then useα+y=2βtofind the value of g. Finally, use the relationtany=y(x+i-r)to find the distance iof the image. (a) Suppose r=12cmand r=12cm. For each of the following values of a, find the position of the image — that is, the position of the point where the reflected ray crosses the central axis:(0.500,0.100,0.0100rad). Compare the results with those obtained with theequation1p+1i=2r.(b) Repeat the calculations for p=4.00cm.

You look down at a coin that lies at the bottom of a pool of liquid of depthand index of refraction(Fig. 34-57). Because you view with two eyes, which intercept different rays of light from the coin, you perceive the coin to bewhere extensions of the intercepted rays cross, at depthdainstead of d. Assuming that the intercepted rays in Fig. 34-57 are close to a vertical axis through the coin, show that da=dn.


You grind the lenses shown in Fig. 34-53 from flat glass disks (n=1.5)using a machine that can grind a radius of curvature of either 40cmor 60cm. In a lens where either radius is appropriate, you select the 40cmradius. Then you hold each lens in sunshine to form an image of the Sun. What are the (a) focal length fand (b) image type (real or virtual) for (bi-convex) lens 1, (c)f and (d) image type for (plane-convex) lens 2, (e) f and (f) image type for (meniscus convex) lens 3, (g) f and (h) image type for (bi-concave) lens 4, (i) fand (j) image type for (plane-concave) lens 5, and (k) f and (l) image type for (meniscus concave) lens 6?

17 through 29 22 23, 29 More mirrors. Object Ostands on the central axis of a spherical or plane mirror. For this situation, each problem in Table 34-4 refers to (a) the type of mirror, (b) the focal distance f, (c) the radius of curvature r, (d) the object distance p, (e) the image distance i, and (f) the lateral magnification m. (All distances are in centimeters.) It also refers to whether (g) the image is real localid="1662999140986" (R)or virtual (V), (h) inverted (I)or non-inverted from (NI)from O, and (i) on the same side of the mirror as the object Oor the opposite side. Fill in the missing information. Where only a sign is missing, answer with the sign.

58 through 67 61 59 Lenses with given radii. An object Ostands in front of a thin lens, on the central axis. For this situation, each problem in Table 34-7 gives object distance p, index of refraction n of the lens, radius r1of the nearer lens surface, and radius localid="1663061304344" r2of the farther lens surface. (All distances are in centimeters.) Find (a) the image distance iand (b) the lateral magnification mof the object, including signs. Also, determine whether the image is (c) real (R)or virtual (V),(d) inverted (I)from the object Oor non-inverted (NI), and (e) on the same side of the lens as object Oor on the opposite side.

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