/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q140P Suppose the farthest distance a ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Suppose the farthest distance a person can see without visual aid is50cm. (a) What is the focal length of the corrective lens that will allow the person to see very far away? (b) Is the lens converging or diverging? (c) The power Pof a lens (in diopters) is equal to1/f, wherefis in meters. What ispfor the lens?

Short Answer

Expert verified
  1. Focal length of the corrective lensf=-0.50cm
  2. The lens is diverging
  3. Power of the lensP=-2.0diopters

Step by step solution

01

Listing the given quantities

Far point of the personi=50cm

02

Understanding the concepts of lens formula and focal length

We will use the lens formula to find the focal length of the lens. The reciprocal of the focal length gives the power of the lens. If the focal length of the lens is negative, it is a diverging lens

Formula:

1f=1p+1i

Power of the lens,

role="math" localid="1663046890549" 1f=p

03

Calculations of the focal length of the corrective lens

(a)

Let’s take the object distance to be at infinity, i.e.,p=∞.

The image is inverted, therefore,theni=-0.50m

1f=1p+1i=1∞+1-0.50

Hence, the focal length of the lens isf=-0.50m

04

Type of the lens

(b)

As f<0, therefore the lens is diverging.

05

Calculations of the power of the lens

(c)

The power of the lens is defined as

P=1f=1-0.50=-2.0diopters

Power of the lensrole="math" localid="1663047184088" P=-2.0diopters

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Prove that if a plane mirror is rotated through an angle a, the reflected beam is rotated through an angle 2α. Show that this result is reasonable for α=45∘.

9, 11, 13 Spherical mirrors. Object O stands on the central axis of a spherical mirror. For this situation, each problem in Table 34-3 gives object distance ps(centimeters), the type of mirror, and then the distance (centimeters, without proper sign) between the focal point and the mirror. Find (a) the radius of curvature r(including sign), (b) the image distance localid="1662986561416" i, and (c) the lateral magnification m. Also, determine whether the image is (d) real (R) or virtual (V), (e) inverted (I) from object O or non-inverted (NI), and (f) on the same side of the mirror as O or on the opposite side.

Figure 34-30 shows four thin lenses, all of the same material, with sides that either are flat or have a radius of curvature of magnitude 10cm. Without written calculation, rank the lenses according to the magnitude of the focal length, greatest first.

A double-convex lens is to be made of glass with an index of refraction of 1.5.One surface is to have twice the radius of curvature of the other and the focal length is to be 60mm. What is the (a) smaller and (b) larger radius?

Figure 34-33 shows an overhead view of a corridor with a plane mirror Mmounted at one end. A burglar Bsneaks along the corridor directly toward the center of the mirror. Ifd=3m, how far from the mirror will she from the mirror when the security guardScan first see her in the mirror?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.