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Sphere Awith mass80kgis located at the origin of an xycoordinate system; sphere Bwith mass60kgis located at coordinates(0.25m,0); sphere Cwith massis located in the first quadrant0.20mfrom Aand0.15mfrom B. In unit-vector notation, what is the gravitational force on Cdue to AandB?

Short Answer

Expert verified

The magnitude of the gravitational force on the sphere C is.

F=-4.4×10-8Nj^

Step by step solution

01

Listing the given quantities

The mass of sphere A ismA=80kg

The mass of sphere B ismB=60kg

The mass of sphere C ismC=0.20kg

The coordinates of sphere A aremA0,0

The coordinates of sphere B aremB0.25m,0

The distance between sphere A and sphere C is rAC=0.20m

The distance between sphere B and sphere C isrBC=0.15m .

02

Understanding the concept of force

We can find the magnitude of force on sphere C due to sphere A and B by using the formula for gravitational force.Then using the cosine law, we can find the angle made by force FBand FA. From this, we can find the magnitude of the net gravitational force on the sphere C due to A and B.

Formulae:

F→=GMmr2r^F1,net→=∑i=1nF1i→

03

Step 3: Calculations ofthe magnitude of force

The magnitude of force on sphere C due to sphere A is given by

FAC=GmAmCrAC2=6.67×10-11800.200.22=2.7×10-8N

The magnitude of force on sphere C due to sphere B is given by

FBC=GmBmCrBC2=6.67×10-11600.200.152=3.6×10-8N

Now, by using cosine rules, we can calculate the angles made by forcesFAandFBas

θA=π+rAC2+rAB2-rBC22rACrAB=π+0.80=217°

In a similar way, the angle made by forceFBwith x axis can be calculated as

θB=rBC2+rAB2-rAC22rBCrAB=-53°
Hence, the net force acting on the sphere C can be written as

F=FACcosθAi+sinθAj+FBCcosθBi+sinθBj

Solving this equation, we get

F=-4.4×10-8Nj^

The magnitude of the gravitational force on the sphere C isF=-4.4×10-8Nj^.

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