/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q42P Figure 13-46a shows a particle聽... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 13: Q42P (page 381)

Figure 13-46a shows a particleAthat can be movedalong ay-axis from an infinite distance to the origin. That origin liesat the midpoint between particlesBandC, which have identical masses, and theyaxis is a perpendicular bisector between them.DistanceDis0.3057m. Figure 13-46b shows the potential energyUof the three-particle system as a function of the position of particleAalong theyaxis. The curve actually extends rightward and approaches an asymptote of-2.7脳1011Jas鈫�鈭�. What are themasses of (a) particlesBandCand (b) particleA?

Short Answer

Expert verified
  1. Masses of particlesB and C are 0.50kg.
  2. Mass of particle A is 1.5kg.

Step by step solution

01

Step 1: Given

Distance,D is0.3057m

02

Determining the concept

Using the formula for gravitational potential energy, find the masses of particles B, C, and A for an infinitely large distance y and y = 0.

The formula is as follows:

U=-GMmR

where, m, and M are masses, R is the radius, G is gravitational constant and U is potential energy.

03

(a) Determining themasses of particles B and C

Now,

U=-GMmR

Applying the Pythagorean Theorem to a graph gives,

U=-GM22D+2GmMy2+D2

where M is the mass of particles B and C is the mass of a particle A .

For an infinitely large term,

2GmMy2+D2=0D=0.3057mU=-GM22DM=0.50kg

Therefore, the masses of a particle BandC are 0.50kg.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The radius Rhand mass Mhof a black hole are related by Rh=2GMh/c2, wherecis the speed of light. Assume that the gravitational acceleration agof an object at a distance r0=1.001Rhfrom the center of a black hole is given byag=GMr2(it is, for large black holes). (a) In terms of Mh, findagat.r0 (b) Doesagatr0 increase or decrease asMhincreases? (c) What isagatr0for a very large black hole whose mass is1.55脳1012times the solar mass of1.99脳1030kg? (d) If an astronaut of height1.70mis atr0with her feet down, what is the difference in gravitational acceleration between her head and feet?(e) Is the tendency to stretch the astronaut severe?

In Problem 1, What ratio m / Mgives the least gravitational potential energy for the system?

A satellite is put in a circular orbit about Earth with a radiusequal to one-half the radius of the Moon鈥檚 orbit. What is its periodof revolution in lunar months? (A lunar month is the period of revolution of the Moon)

Two dimensions.In the figure, three point particles are fixed in place in anx-yplane. ParticleAhas massmA , particleBhas mass2.00mA, and particleChas mass3.00mA. A fourth particleD, with mass4.00mA, is to be placed near the other three particles. In terms of distanced, at what (a)xcoordinate and (b)ycoordinateshould particle Dbe placed so that the net gravitational force on particle Afrom particles B, C, and Dis zero?

Question: A projectile is fired vertically from Earth鈥檚 surface with an initial speed of 10km/s. Neglecting air drag, how far above the surface of Earth will it go?
See all solutions

Recommended explanations on Physics Textbooks

Nuclear Physics

Read Explanation

Magnetism and Electromagnetic Induction

Read Explanation

Electricity and Magnetism

Read Explanation

Electricity

Read Explanation

Kinematics Physics

Read Explanation

Space Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.