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The mean diameters of Mars and Earth are6.9103km and1.3104km , respectively. The mass of Mars is0.11 timesEarth鈥檚 mass. (a) What is the ratio of the mean density (mass perunit volume) of Mars to that of Earth? (b) What is the value of thegravitational acceleration on Mars? (c) What is the escape speedon Mars?

Short Answer

Expert verified
  1. The ratio of the mean density of Mars to Earth is 0.74.
  2. The value of the gravitational acceleration on Mars is 3.8ms2.
  3. The escape speed on Mars is 5103ms.

Step by step solution

01

Step 1: Given

The mean diameter of mars is6.9脳103km.

The mean diameter of the earth is1.3脳104km.

The mass of mars is 0.11 times the mass of earth.

02

Determining the concept

Find the ratio of the density of earth and mars using the formula for density in terms of mass and radius. Using this ratio, find the gravitational acceleration of mars. Also, find the escape velocity using the mass of mars in terms of the mass of earth.

Formulae are as follows:

=34MR3g=GMR2V=GMR

where g is an acceleration due to gravity, M is mass, R is the radius, G is the gravitational constant,and V is volume and p is density.

03

(a) Determining the ratio of the mean density of mars to that of earth

The density of the earth can be written as,

e=Me43Re3

The density of mars can be written as,

m=Mm43Rm3

Now, take the ratio as,

me=MmRe3MeRm3

So,

me=0.110.65104km3.45103km3=0.74

Hence, the ratio of the mean density of Mars to Earth is 0.74.

04

(b) Determining the value of the gravitational acceleration on mars

Gravitational acceleration for mars,

agm=GMmRm2=MmRe2MeRe2GMeRe2=MmRe2MeRm2age

agm=0.110.65104km3.45103km29.8m/s2=3.8m/s2

Hence, the value of the gravitational acceleration on Mars is 3.8ms2.

05

(c) Determining the escape speed on mars

Escape speed can be found as,

v=2GMRmv=26.6710-11Nm2kg-20.115.981024kg3.45106m=5103ms

Hence, the escape speed on Mars is =5103ms.

Therefore, the gravitational acceleration on mars can be found by comparing the densities of earth and the moon. The escape velocity can also be found using the mass and radius of the orbit.

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