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Certain neutron stars (extremely dense stars) are believed to be rotating at about1rev/s. If such a star has a radius of20鈥塳尘, what must be its minimum mass so that material on its surface remains in place during the rapid rotation?

Short Answer

Expert verified

Mass of the material on the surface of the neutron star is51024鈥刱驳

Step by step solution

01

The given data 

1) Frequency of rotation of neutron star is

f=1revs

2)Radius of neutron star isR=20000鈥刴

02

Understanding the concept of Differential acceleration equation 

We use the acceleration difference equation to find the mass of the material on the surface of the neutron star.

Formula:

Acceleration difference equation due to revolution,g=ag2R ... (i)

03

Calculation of the mass of the material 

From equation (i), we can get

ag=GMR2

To stay stationary on the surface of the neutron star, forces should be balanced so that, g= 0.

Hence substituting g=0 in equation (i), we get

0=GMR22RGMR2=2RM=2R3G

Substituting the values of=2f补苍诲鈥R=20000鈥刴we get,

M=21鈥夆赌revs220000鈥夆赌塵36.671011鈥夆赌塏m2/kg2=4.7102451024鈥刱驳

The mass of the material on the neutron star should be51024鈥刱驳.

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