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Certain neutron stars (extremely dense stars) are believed to be rotating at about1rev/s. If such a star has a radius of20 k³¾, what must be its minimum mass so that material on its surface remains in place during the rapid rotation?

Short Answer

Expert verified

Mass of the material on the surface of the neutron star is5×1024 k²µ

Step by step solution

01

The given data 

1) Frequency of rotation of neutron star is

f=1revs

2)Radius of neutron star isR=20000 m

02

Understanding the concept of Differential acceleration equation 

We use the acceleration difference equation to find the mass of the material on the surface of the neutron star.

Formula:

Acceleration difference equation due to revolution,g=ag−Ӭ2R ... (i)

03

Calculation of the mass of the material 

From equation (i), we can get

ag=GMR2

To stay stationary on the surface of the neutron star, forces should be balanced so that, g= 0.

Hence substituting g=0 in equation (i), we get

0=GMR2−Ӭ2RGMR2=Ӭ2RM=Ӭ2R3G

Substituting the values ofÓ¬=2Ï€f²¹²Ô»å R=20000 mwe get,

M=2π×1 â¶Ä‰revs220000 â¶Ä‰m36.67×10−11 â¶Ä‰Nm2/kg2=4.7×1024≈5×1024 k²µ

The mass of the material on the neutron star should be5×1024 k²µ.

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