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In Figure (a), particleAis fixed in place atx=-0.20m on thexaxis and particleB, with a mass of 1.0 kg, is fixed in place at the origin. ParticleC(not shown) can be moved along thexaxis, between particleBandx=∞.Figure (b)shows thexcomponentFnet,xof the net gravitational force on particleBdue to particlesAandC, as a function of positionxof particleC. The plot actually extends to the right, approaching an asymptote of−4.17×1010Nas→∞. What are the masses of (a) particleAand (b) particleC?

Short Answer

Expert verified

a) The mass of particle A is0.25 k²µ

b) The mass of particle B is1 k²µ

Step by step solution

01

The given data

a) Mass of particle B,mB=1 k²µ

b) Distance of particle A from origin,xA=0.2 m(´Ú°ù´Ç³¾´Ú¾±²µ³Ü°ù±ð)

c) Distance of particle B from origin,xB=0 m

d) Distance of particle C from origin,xC=0.4m(fromfigure)

e) Gravitational constant,G=6.67×10−11 N⋅m2/kg2

02

Understanding the concept of Newton’s Gravitational law

Force between two masses can be calculated by using Newton’s law of gravitation. According to Newton’s law of gravitation, the force of two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

Formula:

Gravitational force, F=GMmr2 .......(i)

03

(a) Calculating the mass of particle A

Using equation (i),Force between mass A & B can be written as:

FAB=GmAmBxA24.17×10−10 â¶Ä‰N=6.67×10−11 â¶Ä‰Nâ‹…m2/kg2 â¶Ä‰Ã— â¶Ä‰mA â¶Ä‰Ã— â¶Ä‰1 â¶Ä‰kg0.2 â¶Ä‰m2 â¶Ä‰mA=0.25 k²µ

Hence, mass of the particle A is0.25 k²µ

04

(b) Calculating the mass of particle C

Using equation (i), Force between mass B & C can be written as:

FBC=GmBmCx24.17×10−10 â¶Ä‰N=6.67×10−11 â¶Ä‰Nâ‹…m2/kg2×1 â¶Ä‰â€‰kg × â¶Ä‰mC0.4 â¶Ä‰m2mC=1 k²µ

Hence, mass of particle C is .1 k²µ

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