/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q7P A particle of charge 1.8μ°ä is ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A particle of charge 1.8μ°äis at the center of a Gaussian cube55cmon edge. What is the net electric flux through the surface?

Short Answer

Expert verified

The net electric flux through the surface is 2.0×105N.m2/C.

Step by step solution

01

The given data

  1. Charge of the particle,q=1.8μ°ä
  2. Edge length of cube,a=55cm1m100cm=0.55m
02

Understanding the concept of Gauss law-planar symmetry

Using the concept of Gauss law and the planar symmetry, we can get the required values of the electric field at the left of the plates, right of the plates, and between the plates.

Formula:

The total flux through any surface, ϕ=qε0 (1)

03

Calculation of the net flux through any cube surface

As the cube has six surfaces, thus, the net flux through each surface of the cube is given using equation (1) such that,

ϕ=1.8×10-6C6×8.85×10-12C2/N.m2=2.0×105N.m2/C

Hence, the value of the required flux is2.0×105N.m2/C

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The cube in Fig. 23-31 has edge length 1.40mand is oriented as shown in a region of uniform electric field. Find the electric flux through the right face if the electric field, in Newton per coulomb, is given by (a) 6.00i^,(b) -2.00j^, and -3.00i^+4.00k^(c). (d) What is the total flux through the cube for each field?

A square metal plate of edge length 8.0cmand negligible thickness has a total charge of6.00×10-6C. (a) Estimate the magnitude Eof the electric field just off the center of the plate (at, say, a distance of0.50mmfrom the center) by assuming that the charge is spread uniformly over the two faces of the plate. (b) Estimate Eat a distance of 30m(large relative to the plate size) by assuming that the plate is a charged particle.

Figure 23-24 shows, in cross section, two Gaussian spheres and two Gaussian cubes that are centered on a positively charged particle. (a) Rank the net flux through the four Gaussian surfaces, greatest first. (b) Rank the magnitudes of the electric fields on the surfaces, greatest first, and indicate whether the magnitudes are uniform or variable along each surface.

Figure 23-26 shows four situations in which four very long rods extend into and out of the page (we see only their cross sections). The value below each cross-section gives that particular rod’s uniform charge density in micro-coulombs per meter. The rods are separated by either d or role="math" localid="1661874332860" 2das drawn, and a central point is shown midway between the inner rods. Rank the situations according to the magnitude of the net electric field at that central point, greatest first.

Charge of uniform volume density ÒÏ=3.2 μ°ä/m3 fills a nonconducting solid sphere of radius5.0cm. . What is the magnitude of the electric field

(a) 3.5cmand

(b) 8.0cmfrom the sphere’s center?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.