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A uniform surface charge of density 8.0nC/m2is distributed over the entire x-yplane. What is the electric flux through a spherical Gaussian surface centered on the origin and having a radius of5.0cm ?

Short Answer

Expert verified

The electric flux through a spherical Gaussian surface centered on the origin and having a radius of 5.0 cm is 7.1Nm2/C.

Step by step solution

01

Listing the given quantities

surface charge of density8.0nc/m2

the radius of the Gaussian surface is 5.0 cm

02

Understanding the concept of Gauss Law

Using the statement of Gauss law determine the electric flux through the spherical gauss an surface centered on the origin and having a radius of 5.0 cm

Gauss Law

Formula:

ϕ=qencε0

03

Explanation

From Gauss’s law, we have

Ï•=qencε0=σπ°ù2ε0=8.0×10-9C/m3Ï€(0.050m)2(8.85×10-12C2/N.m2)=7.1Nm2/C

Electric flux through a spherical Gaussian surface centered on the origin and having a radius of 5.0 cm is 7.1N.m2/C

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Most popular questions from this chapter

The electric field at point Pjust outside the outer surface of a hollow spherical conductor of inner radius 10 cmand outer radius 20 cmhas magnitude 450 N/ Cand is directed outward. When a particle of unknown charge Qis introduced into the center of the sphere, the electric field at Pis still directed outward but is now 180 N/C.

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