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The electric field in a particular space isE→=(x+2)i^N/C, with xin meters. Consider a cylindrical Gaussian surface of radius that is coaxial with the x-axis. One end of the cylinder is atx=0 . (a) What is the magnitude of the electric flux through the other end of the cylinder at X=2.0m? (b) What net charge is enclosed within the cylinder?

Short Answer

Expert verified

a) Magnitude of the electric flux through the other end of the cylinder at x = 2.0 m is 0.50N.m2/C

b) Net charge enclosed by the cylinder is 2.2x10-12C.

Step by step solution

01

Listing the given quantities

E→=(x+2)i^N/C

cylindrical Gaussian surface of radius 20 cm

02

Understanding the concept of Gauss law of electrostatics

Using the statement of Gauss law determine the charge enclosed by the cylinder

03

(a) Calculations of electric flux through the other end of the cylinder at x = 2.0 m

There is no flux through the sides, so we have two contributions to the flux, one

from the x = 2.0 m end

ϕ2=+2.0+2N/Cπ0.20m2=0.50N.m2/C

and one from the x = 0 end

ϕ2=+(2N/C)π0.20m2=0.25N.m2/C

Magnitude of the electric flux through the other end of the cylinder at x = 2.0 m is0.50N.m2/C

04

(b) Calculations of charge enclosed by the cylinder

By Gauss’ law, we have

qenc=ε0ϕ2+ϕ0=8.85×10-12C2/N.m2×0.25N.m2/C=2.2×10-12C

The net charge enclosed by the cylinder is 2.2×10-12C

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