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Chapter 23: Q54P (page 683)

Figure 23-58 shows, in cross-section, two solid spheres with uniformly distributed charges throughout their volumes. Each has radius R. Point Plies on a line connecting the centers of the spheres, at radial distance from the center of sphere 1. If the net electric field at point Pis zero, what is the ratio of the total charges?

Short Answer

Expert verified

The ratio of total charges q2/q1 is 1.125

Step by step solution

01

Listing the given quantities

At radial distance R/2 from the center of sphere 1, the net electric field is zero.

02

Understanding the concept of electric field

Using the concept of charge distribution

03

Calculations for the ratio of charges

Inside sphere 1 we have

E=q14蟺蔚0rR3=q14蟺蔚0R/2R3

Outside sphere 2,

q24蟺蔚01r2=q24蟺蔚011.50R2

Equating both we get,

q2q1=98=1.125

The ratio of total charges q2/q1 is 1.125

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Most popular questions from this chapter

Three infinite non-conducting sheets, with uniform positive surface charge densities蟽,2蟽,and 3蟽,are arranged to be parallel like the two sheets in Fig. 23-19a. What is their order, from left to right, if the electric field produced by the arrangement has magnitudeE=0in one region andE=2蟽/蔚0in another region?

Figure 23-51 shows a cross-section through a very large non-conducting slab of thicknessd=9.40mmand uniform volume charge density p=5.80fC/m3 . The origin of an x-axis is at the slab鈥檚 center. What is the magnitude of the slab鈥檚 electric field at an xcoordinate of (a) 0 , (b) 2.0mm , (c) 4.70mm , and (d) 26.0mm?

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