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In Fig. 6-61 a fastidious worker pushes directly along the handle of a mop with a force. The handle is at an angleθwith the vertical, andμsandμkare the coefficients of static and kinetic friction between the head of the mop and the floor. Ignore the mass of the handle and assume that all the mop’s mass mis in its head. (a) If the mop head moves along the floor with a constant velocity, then what is F? (b) Show that ifθ.is less than a certain valueθ0, thenf→(still directed along the handle) is unable to move the mop head. Findθ0.

Short Answer

Expert verified

a)F=μkmgsinθ-μkcosθ

b)θ<θ0=tan-1μs

Step by step solution

01

Given

The handle is at an angle with the vertical,μs andμk are the coefficients of static and kinetic friction between the head of the mop and the floor

02

Understanding the concept

Find the components of force in horizontal and vertical direction. And write the equation in X and Y direction and solve them to find the value of force.

Formula:

F=μkmg²õ¾±²Ôθ-μkcosθ

03

Calculate if the mop head moves along the floor with a constant velocity

(a)

The x component of F contributes to the motion of the crate while its y component indirectly contributes to the inhibiting effects of friction Along the y direction, we haveFN-Fcosθ-mg=0 and along x direction we haveFsinθ-fk=0 (since it is not accelerating, according to the problem). Also,fk=μkFN . Solving these equations for F yields

F=μkmgsinθ-μkcosθ

04

Step 4:  Find θ0

(b)

When θ<θ0=tan-1μs, F will not be able to move the mop head.

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