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Two horizontal forces F1and F2act on a 4.0kgdisk that slides over frictionless ice, on which an x-ycoordinate system is laid out. Force F1is in the positive direction of the xaxis and has a magnitude of 7.0N. Force F2has a magnitude of9.0N. Figure gives the xcomponent Vxof the velocity of the disk as a function of time tduring the sliding. What is the angle between the constant directions of forces F1and F2?

Short Answer

Expert verified

The angle between the two applied forces is 56.

Step by step solution

01

The given data

  • Horizontal forces in positive x-axis direction,F1=7.0N andF2=9.0N.
  • Mass of the disk, m=4.0kg.
02

Understanding the concept of displacement versus time graph

The acceleration is the rate of change of velocity with respect to time. If we have a graph of velocity against time, then the slope of that graph represents the acceleration.

Using a graph, we can find the acceleration of the disk. As we are given that the 1st force is in the horizontal direction, so the 2nd force must be at some angle with x-direction. Using this information and the net acceleration, we can find the angle between them.

Formula:

The force of a body according to Newton鈥檚 second law,

F=ma

localid="1657016494854" (i)

Here, F is the force acting on the body, m is the mass of the body and a is the acceleration of the body.

The acceleration of a body in motion, a=dvdt (ii)

03

Calculation of angle of motion

From the graph

slopeofgraph=y2-y1x2-x1since,x1,y1=0,4andx2,y2=3,5=5--43-0=93=3

Slope of graph = Acceleration of the motion (from equation (ii))

=3m/sThegraphisadisplacementvstimegraph

Again, substituting the values in equation (i), we get force in x-direction. Substitute the x component of forces, the mass and acceleration values in equation (i) to calculate the angle.

role="math" localid="1657017376723" Fx=max

F1+F2cos=4kg3m/s2

7.0N+9N肠辞蝉胃=12N

9N肠辞蝉胃=12N-7N

cos=59

=cos-10.55

=56.25

56

Hence, the angle of motion is 56.

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