91影视

I)i) Mass of alligator,$m=130kg$

ii Top head surface area of alligator,$A=0.20m^2$

iii) Swallow stones has massof $1.0\text{\%}$mass of alligator

Using Archimedes' principle, we can say that the weight of the body that sinks or is submerged in a liquid is equal to the weight of that liquid, which is displaced. Also, the mass and volume are directly proportional to each other.

Formula:

Buoyant force exerted by fluid on a body, ${\text{F}}_{\text{b}}={\text{蚁}}_{\text{w}}脳\text{g}脳\text{v}$ (i)

Density of a material,$\text{蚁}=\frac{\text{m}}{\text{v}}$ (ii)

Using equation (i) and the given values, we get

$\begin{array}{c}{m}_A脳g={蚁}_w脳g脳v\text{(}鈭�{\text{F}}_b{\text{=m}}_A脳\text{g)}\\ m_A={蚁}_w脳v\\ 130=1000v\\ v=0.13m^3\end{array}$

Now,themass is increased by$1.0\text{\%}$. Then the volume will increase by the same.

So, new increased volume is

$\begin{array}{c}\text{V}=0.01\text{v+v}\\ =\left(0.13\right)\left(1.01\right)\\ =1.3脳{10}^{鈭�3}{m}^3\end{array}$

Now, fromthetop head surface area and above volume, we can find the distance/depth by whichthealligator sinks:

$\begin{array}{c}Volume=Area脳Depth\\ 1.3脳{10}^{鈭�3}=0.20脳Depth\\ Depth=6.5脳{10}^{鈭�3}m\end{array}$

Hence, the alligator sinks at a depth of$6.5脳{10}^{鈭�3}m$$6.5脳{10}^{鈭�3}m$