91Ó°ÊÓ

Measured height$h=740.35\mathrm{mm}$

Density of mercury,$\mathrm{ÒÏ}=1.3608×{10}^4\mathrm{kg}/{\mathrm{m}}^3$

Free fall acceleration at site of barometer, $g=9.7835\mathrm{m}/{\mathrm{s}}^2$

To find pressure, we can use the formula in terms of density, acceleration, and height. We can convert the pressure from Pascal to torr using the conversion factor.

Formula:

Pressure applied on a body, (i)

$1\mathrm{torr}=133.33\mathrm{Pa}$

Atmospheric pressure in Pascal using equation (i) is given as:

$$\begin{gathered} p=1.3608×{10}^4\mathrm{kg}/{\mathrm{m}}^3×9.7835\mathrm{m}/{\mathrm{s}}^{2}x0.74035\mathrm{m} \\ =98565.66\mathrm{Pa}.....................................\left(\mathrm{a}\right) \end{gathered}$$

Hence, the value of pressure in Pascal is$98565.66Pa$

From equation (a), we get the pressure, hence

$$\begin{gathered} p=98565.66\mathrm{Pa}×\frac{1\mathrm{torr}}{133.33\mathrm{Pa}}(âˆ\mu 1\mathrm{torr}=133.33\mathrm{Pa}) \\ =739.26\mathrm{torr} \end{gathered}$$

Hence, the value of pressure in torr is role="math" localid="1657194537605" $739.26\mathrm{torr}$.