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Calculate the (a) upper and (b) lower limit of the Brewster angle for white light incident on fused quartz. Assume that the wavelength limits of the light are 400 and 700 nm.

Short Answer

Expert verified

a) The upper limit of the Brewster angle is.55.8°

b) The lower limit of the Brewster angleis .55.5°

Step by step solution

01

Given data

  • The white light is incident on fused quartz.
  • The wavelength limits of the light are.400 n³¾²¹²Ô»å700 n³¾
02

Understanding the concept of Brewster angle

The special angle of incidence that produces a 90 degrees angle between the reflected and refracted ray is called the Brewster angle. If an unpolarized beam of light is incident on a boundary between two media at Brewster angle, the reflected wave will be fully polarized. For this situation, the tan of the Brewster angle is equal to the ratio of refractive indices of the two media.

Formula:

The Brewster angle is related to the refractive indices of the two mediaas,

θB=tan−1n2n1⋅⋅⋅⋅⋅⋅(1)

03

a) Calculation of the upper limit of Brewster angle

Here, the two media are fused quartz and air. Son1=1. The value of n2 will be different for the two given wavelengths.

The standard values aren2=1.47for wavelength 400 nm andn2=1.455for wavelength = 700 nm considering refracting index is inversely proportional to wavelength.

Thus, we calculate the upper limiting value of the Brewster angle using equation (1) as follows:

localid="1664201175448" (θB)up=tan−11.471=55.8°

Hence, the value of the upper limit is.55.8°

04

b) Calculation of the lower limit of Brewster angle 

Now, we calculate the lower limiting values of the Brewster angle using equation (i) as follows:

(θB)low=tan−11.4551=55.5°

Hence, the value of the lower limit is.55.5°

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Most popular questions from this chapter

Question: Figure depicts a simplistic optical fiber: a plastic core(n1=1.58)is surrounded by a plastic sheath (n2=1.53). A light ray is incident on one end of the fiber at angle.The ray is to undergo total internal reflection at point A, where it encounters the core–sheath boundary. (Thus there is no loss of light through that boundary.) What is the maximum value of θthat allows total internal reflection at A?

Figure:

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Figure:

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