91Ó°ÊÓ

The polarization direction of the sheet is initially parallel with the y axis.

The sheet is rotated $40°$clockwise.

Light can be polarized by passing it through a polarizing filter or other polarizing material. The intensity of an unpolarized light after passing through a polarized filter is given by the cosine-square rule. Here, we need to use the concept of polarization using polarizing sheets along with the equations for the intensity of light passing through the polarizing sheet.

Formulae:

If the incident light is un-polarized, then the intensity of the merging light using the one-half rule is given by,

$I=0.5I_0$ (i)

If the incident light is already polarized, then the intensity of the emerging light is cosine –squared of the intensity of incident light,

$I=I_0{\cos }^2\mathrm{θ}$ (ii)

Here $\mathrm{θ}$is the angle between the polarization of the incident light and the polarization axis of the sheet.

When the incident light is initially un-polarized, the intensity of light emerging from the sheet is given by equation (i), that is $I=0.5I_0$.

As, the intensity does not depend on the angle; thus, the fraction of intensity will remain the same.

As the incident light is initially polarized parallel to the x-axis and the polarizing direction of the sheet is parallel to the y-axis. No light can pass through the sheet. But when we rotate the sheet, some light can pass as a component and is given by equation (ii) as $I=I_0{\cos }^2\mathrm{θ}$:

So, the fraction of light is increased by ${\cos }^2\mathrm{θ}$.

As the incident light is initially polarized parallel to the y-axis, and the polarizing direction of the sheet is also parallel to the y-axis. All light can pass through the sheet.

But when we rotate the sheet, some light can be blocked, and the intensity of light emerging out is given using equation (ii) by, $I=I_0{\cos }^2\mathrm{θ}$

So, the fraction of the light decreases by ${\cos }^2\mathrm{θ}$.